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Vinvika [58]
4 years ago
10

A gas has ? Please help will appreciate it. Thanks

Chemistry
1 answer:
Kaylis [27]4 years ago
6 0
Answer is C. No definite shape or definite volume
A gas<span> is a substance with no </span>definite volume<span> and no </span>definite shape<span>. Solids and liquids </span>have volumes<span> that do not change easily. A </span>gas<span>, on the other hand, </span>has<span> a vol- ume that changes to match the </span>volume<span> of its container. The molecules in a </span>gas<span> are very far apart compared with the molecules in a solid or a liquid.</span>
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Now you will use your answers from the four questions above to write your lab report. Follow the directions below.
ivann1987 [24]

Answer:

WHere is the directions?

Explanation:

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3 years ago
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Identify the precipitate(s) of the reaction that occurs when a silver nitrate solution is mixed with a sodium chloride solution.
klio [65]
Hello!

The precipitate of the reaction that occurs <span>when a silver nitrate solution is mixed with a sodium chloride solution is silver chloride (AgCl). 

The chemical equation for this precipitation reaction is the following:

AgNO</span>₃(aq) + NaCl(aq) → AgCl↓(s) + NaNO₃(aq)

Silver Chloride is a chemical compound that is poorly soluble in water because the chemical bond between Ag⁺ and Cl⁻ is very strong as the two ions are nearly the same size and have similar electronic densities. If the chemical bond is strong, it is more difficult for water molecules to break this bond to surround the individual ions, and thus solubility will decrease. 

Have a nice day!
7 0
3 years ago
Given the following balanced equation at 120°C: A(g) + B(g) ⇋ 2 C(g) + D(s)(a) At equilibrium a 4.0 liter container was found to
BlackZzzverrR [31]

Answer:

a) kc = 0,25

b) [A] = 0,41 M

c) [A] = <em>0,8 M</em>

[B] =<em>0,2 M</em>

[C] = <em>0,2M</em>

Explanation:

The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.

Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.

If global reaction is:

A(g) + B(g) ⇋ 2 C(g) + D(s)

The kc = \frac{[C]^2}{[A][B]}

a) The concentrations of each compound are:

[A] = \frac{1,60 moles}{4,0 L} = <em>0,4 M</em>

[B] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

[C] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

<em>kc = </em>\frac{[0,1]^2}{[0,4][0,1]} = 0,25

b) The addition of B and D in the same amount will, in equilibrium, produce these changes:

[A] = \frac{1,60-x moles}{4,0 L}

[B] = \frac{0,60-x moles}{4,0 L}

[C] = \frac{0,60+2x moles}{4,0 L}

0,25 = \frac{[0,60+2x]^2}{[1,60-x][0,60-x]}

You will obtain

3,75x² +2,95x +0,12 = 0

Solving

x =-0,74363479081119   → No physical sense

x =-0,043031875855476

Thus, concentration of A is:

\frac{1,60-(-0,04 moles)}{4,0 L} = <em>0,41 M</em>

c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:

[A] = \frac{1,60 moles}{2,0 L} = <em>0,8 M</em>

[B] = \frac{0,40 moles}{2,0 L} = <em>0,2 M</em>

[C] = \frac{0,40 moles}{2,0 L} = <em>0,2M</em>

I hope it helps!

8 0
4 years ago
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How does the energy provided by the Sun affect global ocean currents?
777dan777 [17]
The answer is C. The sun heats waters near the equator, which then move toward the polls where the waters cool.
8 0
3 years ago
How many moles are in a 13.7g block of calcium?
goldenfox [79]
<h3>Answer:</h3>

0.342 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

13.7 g Ca

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 13.7 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})
  2. Multiply/Divide:                 \displaystyle 0.341816 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.341816 mol Ca ≈ 0.342 mol Ca

6 0
3 years ago
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