All categories

3 years ago

What is the area of a regular hexagon with sides that measure 10 feet and an

Mathematics

1 answer:

kap26 [50]3 years ago

3 0

Answer:

259.8 square feet

Step-by-step explanation:

What is the area of a regular hexagon with sides that measure 10 feet and an

apothem that measures 8.66 feet?

The formula to solve the above question is given as:

Area = (3√3 s²)/ 2 where

s is the length of a side of the regular hexagon

Area of this Hexagon is calculated as:

= (3√3 × 10²)/2

= 3√3 × 100/2

= 259.80762114 square feet

Approximately = 259.8 square feet

The area of the regular hexagon = 259.8 square feet

You might be interested in

The difference of four times a number and seven is thirteen

Scrat [10]

4n - 7 = 13

4n = 20
n = 5. Hope it helps!

6 0

3 years ago

Find the value of the variables

Ierofanga [76]

Answer:

Your answer is.....

x= 10.58

y= 21.66

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

4 0

3 years ago

In the equation 5x-2=-x-20, What is the value of x? a. 2 b. -1 c. -3 d. -2

mestny [16]

Answer:

C choice.

Step-by-step explanation:

$5x - 2 = - x - 20 \\$

First, we move the same terms to the same side.

$5x + x = - 20 + 2 \\ 6x = - 18$

Then we move 6 to divide - 18.

$x = \frac{ - 18}{6} \\ x = - 3$

7 0

2 years ago

Plz help, I need help!!!!

Otrada [13]

Answer:

56 multiplied by 9 = 504

Step-by-step explanation:

55.8 rounded is 56, and 9.12 rounded is 9

4 0

2 years ago

F(x)=x+1, g(x)=-x, and h(x)=x^2+1 find (g of)(x)

Dvinal [7]

Answer:

Step-by-step explanation:

6 0

3 years ago