Avagadros constant states that there are 6.022 x 10²³ units in 1 mol of substance.
These units could be atoms that make up an element, or molecules making up a compound or ions as well.
1 mol of O₂ contains - 6.022 x 10²³ molecules of O₂
molecular mass of O₂ is (16*2) = 32 g/mol
1 mol of O₂ weighs = 32 g
Therefore in 32 g of O₂ - 6.022 x 10²³ O₂ molecules
gas tank contains O₂ weighing 650 g
in 1 g - 6.022 x 10²³/32 molecules
in 650 g - 6.022 x 10²³/32 * 650
= 2.96 x 10²² molecules of O₂
Answer:
528.25 Calories
Explanation:
From the question given above, the following data were obtained:
Energy in Joules = 2210.20 J
Energy in calories =?
We can convert 2210.20 J to calories by doing the following:
4.184 J = 1 cal
Therefore,
2210.20 J = 2210.20 J × 1 cal / 4.184 J
2210.20 J = 528.25 Calories
Thus, 2210.20 J is equivalent to 528.25 Calories.
Answer:
In elxplaination
Explanation:
Phase Change:s Evaporation, Condensation, Freezing, Melting, Sublimation & Deposition.
<span>what volume of ammonia must you measure?
1.50 moles NH3 ( 22.4 L / 1 mole ) = 33.6 L NH3 should be measured
</span><span>how many molecules of nacl are in 23.40 grams nacl
23.40 g NaCl ( 1 mol / 58.44 g) (6.022 x 10^23 molecules / 1 mol ) = 2.4113 x 10^23 molecules
Hope these answer the questions. Have a nice day.</span>
Mass=density·volume. The density is 2.70g/mL and the volume is 353mL. So you would multiply 2.70g/mL by 353mL which will give you 953.1g. Hope that helps :)