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Westkost [7]
3 years ago
13

Can you please explain why the metal doesn't rust at b

Chemistry
1 answer:
Anna71 [15]3 years ago
7 0

(a)  (i) Zinc blende is mainly Zinc sulphide and in industry it is converted to ZnO by flames to burn off the sulphur as SO2 which is then used to make sulphuric acid.

(ii)   Reduction of ZnO to Zn:-

2ZnO + C = CO2 + 2Zn

(b) This is called sacrificial anodic protection.  The zinc ( which is more reactive than iron) when in contact with the oxygen in the air is oxidised and in the process loses its electrons. These travel  through the electrolyte to the iron. The electrons then reduce any iron oxide to iron: fe2+ + 2e  ---> Fe.


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What are the uses of polythene?
Crank
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Polyethylene is manufactured in three different forms namely:

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Each of these three plastics has different applications ranging from containers, packaging and films to buckets and bottles.

Hope it helps you...
7 0
3 years ago
Read 2 more answers
Four moles of Argon gas are at a pressure of 1.90 atm, and the temperature is 50 degrees C. What is the volume of the gas?
soldier1979 [14.2K]
N = 4 moles of Ar2, P = 1.90 atm, V = ?
T = 50C = 273 + 50K = 323K
PV = nRT --> V = nRT/P
V = (4)(.0821)(323)/1.90
V = 106.07/ 1.9
V = 55.8 L
4 0
3 years ago
Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution
Fantom [35]

Answer:

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

I hope it's helpful!

7 0
3 years ago
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

3 0
3 years ago
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to
AlekseyPX

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength 6.32x10^{-36}m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

\lambda =\frac{h}{m*v}

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m

Best regards!

7 0
3 years ago
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