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garik1379 [7]
3 years ago
12

What is the chemical symbol for the starting substance 2nacl+2h2o->2naOH+cl2+h2

Chemistry
1 answer:
ruslelena [56]3 years ago
6 0
He symbol "=" is used to 
<span>starting substance </span>
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(a) The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the
Vaselesa [24]

Answer:

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

Explanation:

Average rate of the reaction is defined as ratio of change in concentration of reactant with respect to given interval of time.

R_{avg}=-\frac{[A]_2-[A]_1}{t_2-t_1}

Where :

A_1 = initial concentration of reactant at t_1.

A_2 = Final concentration of reactant at t_2.

2A+3B → 3C+2D

R_{avg}=-\frac{1}{2}\frac{[A]_2-[A]_1}{t_2-t_1}

The concentration of A at (t_1=0 seconds ) = A_1=0.0400 M

The concentration of A at (t_2=20 seconds ) = A_2=0.0240 M

The average rate of reaction in terms of the disappearance of reactant A in an interval of 0 seconds to 20 seconds is :

R_{avg}=-\frac{1}{2}\times \frac{0.0240 M-0.0400 M}{20-0}=0.0004 M/s

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

6 0
3 years ago
What is a measureing tape used for​
Goryan [66]

Answer:

It is used to measure size or distance.

7 0
3 years ago
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A 12.00 g milk chocolate bar is found to contain 8.000 g of sugar. What will be the amount of sugar in milligrams if the size of
Ainat [17]
Answer is: amount of sugar in milk chocolade is 3333 mg.
To solve this question, make proportion: if 12,00 grams of milk chocolate contain 8,00 grams of sugar, than 5,00 grams contain:
12,000 g : 8,000 g = 5,000 g : m(sugar).
12,000 g · m(sugar) = 8,000 g · 5,000 g.
m(sugar) = 40,000 ÷ 12,000.
m(sugar) = 3,333 g = 3333 mg.
3 0
3 years ago
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Thermal energy naturally flows from _________ matter to _______ matter.
Firlakuza [10]

Answer:

Warmer

Cooler

Explanation:

5 0
3 years ago
Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).
Phantasy [73]

Answer: 6.38\times 10^{23} molecules of water are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles

The balanced chemical reaction is:

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O  

According to stoichiometry :

2 moles of Fe_2O_3 produce = 3 moles of H_2O

Thus 0.707 moles of Fe_2O_3 will produce=\frac{3}{2}\times 0.707=1.06moles  of H_2O  

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus 1.06 moles of H_2O contains = \frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23} molecules

5 0
3 years ago
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