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gladu [14]
3 years ago
14

A student cuts out a rectangular strip of paper that has an area of 2/3 square meter. If the width of the paper strip is 1/5 met

er, what is the length of the strip, in meters?​
Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:length of the strip =3 1/3 meters

Step-by-step explanation:

Step 1

Given that

Area of the rectangular strip= 2/3 square meter

width = 1/5 meter

length = ?

W e know that the formulae for area of a rectangle =  Length x width

using this equation, we will solve for length

Step 2

area of  the rectangular strip=  Length x width

Length = Area / Width

2/3 square meter / 1/5 meter

Length= 2/3 x 5/1 = 10/3= 3 1/3 meter

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Using the z-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

<h3>What are the hypothesis?</h3>
  • At the null hypothesis, it is tested if Zwerg cannot correctly follow this type of direction by an experimenter more than 50% of the time, that is:

H_0: p \leq 0.5

  • At the alternative hypothesis, it is tested if Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time, that is:

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The <em>test statistic</em> is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

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For this problem, the parameters are:

n = 48, \overline{p} = \frac{37}{48} = 0.7708, p = 0.5

The value of the <em>test statistic</em> is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

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Since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

To learn more about the z-distribution, you can take a look at brainly.com/question/16313918

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