Answer:
14.53ML
Explanation:
V1=218
V2=?
P2=15p1
USING BOYLE'S LAW
P1V1=P2V2
V2=P1V1/P2=P1(218ML)/15P1
=14.53ML
Answer:
44.8 L of O2 will react (option D)
Explanation:
Step 1: Data given
Number of moles of SO2 = 4.00 moles
STP = Pressure = 1 atm and temperature = 273 K
Step 2: The balanced equation
2 SO2(g) + O2(g) → 2 SO3(g)
Step 3: Calculate moles of O2
For 2 moles SO2, we need 1 mol O2 to produce 2 moles SO3
For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2
Step 4: Calculate volume of O2
For 1 mol we have a volume of 22.4 L
V = (n*R*T)/ p
V = (2.00 * 0.08206 * 273)/p
V = 44.8 L
For 2.00 moles we have a volume of 2*22.4 = 44.8 L
44.8 L of O2 will react (option D)
I think this is it
Cd(HCO3)2---->CdCO3+H2O+CO2
Sorry if this is wrong
<span>Add 3 x 10^9 +5.3 x 10^10
</span><span> 3 x 10^9
+5.3 x 10^10
</span>------------------
5.6 x 10^10
<span>Carrier Gas, Flow Controller, Column, Detector, Recorder
</span>First we have a cylinder containing the
carrier gas. From there, the carrier gas goes to the flow controller, which determines
how much carrier gas we are entering into the column (it doesn’t let more gas
pass through). Then, the carrier gas enters the column, which is the most
important part of the device. The sample enters the column from another place:
the injector. Then, the sample and the carrier gas go together across the
column. The interactions between the sample and the column will determine how
fast each sample component goes through the column, and so: which component
gets out earlier. So, at the end, you will have isolated each substance. Then,
each one passes (alone) through the detector, which measures something about
the sample – this information will let you know which substance it is. Finally,
the recorder provides you with the information the detector has found.
Nowadays, the recorder is a computer. In the “stone age” they just used a rudimentary
printer.
