The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
brainly.com/question/26374513
Answer:
6.67 M
Explanation:
Molarity = 
<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>
200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH
750 mL x (1 L/1000 mL) = 0.750 L
<em>Substitute values into the equation.</em>
Molarity = 
Molarity = 6.667... M
Molarity = 6.67 M
in 6.0 years it will be 450.00 heart beats
in 6.00 years it will be 450.000 heart beats
in 6.000 years it will be 450.0000 heart beats
Explanation:
Answer:
D. concentration, as the concentrations of reactants and products remain unchanged after equilibrium is reached.
Explanation:
I put it for the test and i got right hehe
Answer:
First check to make sure you have a balanced equation
Second use mole ratios to set up what you need to know
Finally convert the moles to grams using the correct molecular weight
I will get you started
According to the reaction above, one mole of Magnesium Nitrate is produced from 2 moles of Nitric Acid
1 mole of Mg(NO3)2/2 moles of HNO3
5 grams of Nitric acid contains
5 g * 1 mole/63 g of Nitric Acid = 0.079365079 moles
Explanation:
