The first statement is true. To remember this, ionic compounds are a mix of the two different types of elements (metal/nonmetal). Electrons are transferred from one atom to the other.
V=84.0 mL = 84.0 cm³
m=609.0 g
p=m/v
p=609.0/84.0=7.25 g/cm³
To determine the volume of the gas mixture, we first need to determine the total pressure of the mixture. To do this, we use the definition of the partial pressure of a component in the gas mixture. The partial pressure is the pressure of a component as if it were alone in the container. It is equal to the mole fraction of the component times the total pressure of the system. From this, we determine total pressure.
Pneon = xneonP
P = Pneon / xneon
P = 8.87 kPa / (225 / (225 + 320 + 175))
P = 8.87 kPa / 0.3125 = 28.384 kPa
Assuming ideal gas, we use PV=nRT to calculate for the volume,
PV = nRT
V = nRT / P
n = 225 mg ( 1 mmol / 20.18 mg) + 320 mg ( 1 mmol / 16.05 mg ) + 175 mg ( 1 mmol / 39.95 mg ) = 35.47 mg = 35467.0 g
V = 35467.0 (8.314) (300) / (28384) = 3116.68 m^3
A substance which turns universal indicator blue. It’s not pH 1 cause it’s acidic. And pH 7 is neutral not alkali.
Hope u understood.
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Answer:
19.5g is the theoretical yield of alum
Explanation:
Based on the balanced reaction, 4 moles of sulfuric acid produce 2 moles of alum. To solve this question we need to find the moles of H2SO4. With these moles we can find the moles of alum and its mass assuming all sulfuric acid reacts producing alum.
<em>Moles Sulfuric Acid:</em>
8.3mL = 0.0083L * (9.9mol/L) = 0.08217 moles sulfuric acid
<em>Moles Alum:</em>
0.08217 moles sulfuric acid * (2mol KAl(SO4)2•12H2O / 4mol H2SO4) =
0.041085 moles KAl(SO4)2•12H2O
<em>Mass Alum -Molar mass: 474.3884 g/mol-</em>
0.041085 moles KAl(SO4)2•12H2O * (474.3884 g/mol) =
<h3>19.5g is the theoretical yield of alum</h3>