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tia_tia [17]
3 years ago
8

A gas mixture consists of 320 mg of methane, 175 mg of argon, and 225 mg of neon. the partial pressure of neon at 300k is 8.87 k

pa. calculate (i) the volume and (ii) the total pressure of the mixture.
Chemistry
1 answer:
Vladimir [108]3 years ago
5 0
To determine the volume of the gas mixture, we first need to determine the total pressure of the mixture. To do this, we use the definition of the partial pressure of a component in the gas mixture. The partial pressure is the pressure of a component as if it were alone in the container. It is equal to  the mole fraction of the component times the total pressure of the system. From this, we determine total pressure.

Pneon = xneonP
P = Pneon / xneon
P = 8.87 kPa / (225 / (225 + 320 + 175))
P = 8.87 kPa / 0.3125 = 28.384 kPa

Assuming ideal gas, we use PV=nRT to calculate for the volume,
PV = nRT
V = nRT / P

n = 225 mg ( 1 mmol / 20.18 mg) + 320 mg ( 1 mmol / 16.05 mg ) + 175 mg ( 1 mmol / 39.95 mg ) = 35.47 mg = 35467.0 g 

V = 35467.0 (8.314) (300) / (28384) = 3116.68 m^3
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GIVING 20 POINTS!! Apply Concepts Two chemists each plan an investigation in which they will combine hydrogen gas with chlorine
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Answer:

Yes, the investigations will reach similar conclusions about the reactivity of H2 and Cl2

Explanation:

1. The law of multiple proportions says that when elements form compounds, the proportions of the elements in those chemical compounds can be expressed in small whole number ratios.  This means that regardless of whether 1000 times more of the products are used, the reactivity of the products is established by the chemical reaction

2. The law of multiple proportions is an extension of the law of definite composition, which states that compounds will consist of defined ratios of elements.

3. A reaction with more reactants will need more care because more products are produced, which can be toxic

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When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.
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Write the equilibrium expression of each chemical equation.<br> 2H2S(g) 2H2(g) + S2(g)
hodyreva [135]

Answer:

<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u>

Explanation:

2H2S(g)⇋2H2(g)+S2(g)2H2S(g)⇋2H2(g)+S2(g)

The equilibrium constant expression in terms of concentrations is:

Kc=<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u><u>.</u>

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2 years ago
Three common gaseous compounds of nitrogen and oxygen of different elementary composition are known: (A) laughing gas containing
Ede4ka [16]

Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

This means that the mass of oxygen will be (1-0.6365) = 0.3635g

B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

0.3635: 0.5332: 0.6955

Divide this ratio by the smallest number (0.3635)

0.3635/0.3635 = 1

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Multiply this ratio by 2, we have:

2: 2.9 : 3.8

Hence, the simple whole number ratio is 2:3:4.

This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

4 0
3 years ago
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