Answer:
4.55 * 10^23 molecules
Explanation:
This is a conversion problem. We know that one mole has 6.022 *10^23 particles or molecules so we can use this as a conversion factor.
0.755 mol ( 6.022*10^23 molecules/ 1 mol)
=4.55*10^23 molecules
She might’ve wanted to wait for the water to reach boiling point to count the bubbles
Answer:
The molarity of the HCl solution is 0.17M
Explanation:
When a titration occurs between an acid and a base it is called neutralization.
The formula to calculate the concentration of the acid is:
Ca*Va=Cb*Vb
where Ca and Cb are the concentrations of the acid and the base respectively and Va and Vb are the volumes of the acid and the base.
As HCl is an acid, solve the equation for Ca:
Replacing values:
Therefore the molarity of the HCl solution is 0.17M
Answer:
2.93g
Explanation:first, let us calculate the number of mole of NaCl present in the solution. This is illustrated below:
Molarity = 0.5M
Volume = 100cm^3 = 100/1000 = 0.1L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole of NaCl = 0.5 x 0.1 = 0.05mole
Now we can obtain the mass of NaCl as follows:
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mole of NaCl = 0.05mol
Mass of NaCl =?
Mass = number of mole x molar Mass
Mass of NaCl = 0.05 x 58.5
Mass of NaCl = 2.93g
Answer:you observe the light?
Explanation:
