Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
x > - 3/7
Step-by-step explanation:
6x - 2x - 4 > 2 - 3 (x + 3)
6x - 2x - 4 > 2 - 3x - 9
4x - 4 > 2 - 3x - 9
4x - 4 > - 7 - 3x
4x - 4 + 3x > - 7
7x > - 7 + 4
7x > - 3
Hello!
This submarine rose 100 feet (+100) and then descended (-100). Usually in an equation this would cancel out and make 0. Therefore, our answer is 0.
I hope this helps!
Answer: 1
Step-by-step explanation:
1. 2 4/16 + 3 2/3 = 2 12/48 + 3 32/48 = 71/12 reduced is 5 11/12
( lcm of 16 and 3 is 48)
2. 6 11/12 - 5 11/12 = 1
Please give me a brainliest i did all my hard work. The answer 1 is 100% right.
40 kph is equal to abt 11 mps so that means 40kph is faster