Question

I need huge help understanding this type of questions :( Please and thank you

Answer 1

Answer:

67.28 N

Explanation:

Given that,

The mass of an box, m = 15.2 kg

The coefficients of static and kinetic frictions for plastic on wood are 0.55 and 0.36, respectively.

The force of static friction,

$F_s=\mu_smg\\\\F_s=0.55\times 15.2\times 9.8\\\\F_s=81.92\ N$

The force of kinetic friction,

$F_k=\mu_kmg\\\\F_k=0.36\times 15.2\times 9.8\\\\F_k=53.62\ N$

Net force acting on the object is :

F = 120.9 -53.62

= 67.28 N

Hence, this is the required solution.