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shtirl [24]
4 years ago
11

What is the universe made of? Astronomers face an embarrassing conundrum: they don't know what 95% of the universe is made of​

Physics
1 answer:
rewona [7]4 years ago
3 0

Answer:

This what they all been waiting for

I guess so

They been waiting for this sh,it for a long time didn't they

I'ma give it everything I got

Ayo Dougie park that X6 around the corner

Aye I'm just feeling my vibe right now

I'm feeling myself

Explanation:

You might be interested in
Yung's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a sc
Lady bird [3.3K]

Answer:

1.082 mm

Explanation:

From the question, we can see that we were given The following

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1.1 m

We know that Y(20) = 10.2 mm = 10.2*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1.1 * 502*10^-9)/10.2*10^-3

d = 1.1*10^-5 / 10.2*10^-3

d = 1.082 mm

Therefore, we can say that the distance of separation between the two slits is 1.082 mm

4 0
4 years ago
Assume that, when we walk, in addition to a fluctuating vertical force, we exert a periodic lateral force of amplitude 25 NN at
dexar [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  F = 25 \  N

   The frequency is   f = 1 \  Hz

   The mass of the bridge per unit length is  \mu  =  2000 \  kg /m

    The length of the central span is  d =  144 m

     The oscillation amplitude of the section  considered at the time considered is  A = 75 \ mm =  0.075 \  m

      The time taken for the undriven oscillation to decay to \frac{1}{e}  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            m =  \mu  *  d

=>        m =  2000 * 144

=>        m =  288000 \ kg

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 A(t) = A_o e^{-\frac{bt}{2m} }

Here b is the damping constant and the A_o is the amplitude of the section when it was undriven

So from the question  

               \frac{A_o}{e}  = A_o e^{-\frac{b6T}{2m} }

=>            \frac{1}{e}  =e^{-\frac{b6T}{2m} }

=>          e^{-1} =e^{-\frac{b6T}{2m} }

=>           -\frac{3T b}{m}  =  -1

=>         b  = \frac{m}{3T}

Generally the amplitude of the section considered is mathematically represented as

           A =  \frac{n * F }{ b *  2 \pi }

=>       A =  \frac{n * F }{ \frac{m}{3T}  *  2 \pi }

=>       n =  A  *  \frac{m}{3}  *  \frac{2\pi}{25}

=>       n = 0.075 *  \frac{288000}{3}  *  \frac{2* 3.142 }{25}

=>       n = 1810 \ people

3 0
3 years ago
Help me please asap :(
mixer [17]
17. a
18. c
19. a
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8 0
3 years ago
How do x ray measurements help us measure the amount of dark matter in galaxy clusters?
Kruka [31]

The temperature of the darc spaces can sometimes hike to extremely hot temperatures. Some amount of energy due to trapping matter inside is liberated and turned into light which can be seen in X-rays.

<h3>What are x-rays?</h3>

A piercing type of high-energy electromagnetic radiation is called X-radiation. The majority of X-rays have a wavelength between 10 picometers and 10 nanometers, which equates to frequencies between 30 petahertz and 30 exahertz.

X-ray scans show that a galaxy cluster's intergalactic region is extremely hot. This is due to the fact that the intergalactic medium, also known as the intergalactic media, is primarily composed of heated, ionized hydrogen with traces of heavier elements like silicon, carbon, and oxygen.

Instruments to detect X-rays must be transported to high altitudes by balloons, sounding rockets, and satellites since X-radiation is absorbed by the Earth's atmosphere.

To learn more about X-rays, here

brainly.com/question/12947180

#SPJ4

8 0
2 years ago
Explain why meteorologists compare new weather maps and weather maps that are 24 hours old​
lawyer [7]

To see which way atmospheric conditions and meteorological phenomena are moving, and how fast.

Also to see whether they were correct yesterday.

3 0
4 years ago
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