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Scorpion4ik [409]
1 year ago
12

Proper use of the friction zone makes it easier to:.

Physics
1 answer:
yulyashka [42]1 year ago
4 0

Friction is the opposition offered to the movement of a surface on another and depends on the nature of the surfaces in contact.

<h3>What is friction?</h3>

The term friction refers to the opposition that is offered by surfaces in contact when they move over each other. The question is incomplete but I will try to help you the much I can.

Now recall that fricton only depends on the nature of the surfaces in contact. The friction is te reason when heat is provides in the moving parts of machines.

Learn more about friction: brainly.com/question/15117038

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Why is it important to know the location of active and inactive faults in our country?
Andrew [12]

Answer:

I hope this helps.

Explanation:

It's important to know the location of an active fault in order to determine the magnitude of the expected earthquake. There is a chance than an inactive fault can become active again. It's important that we take the locations into account in order to be prepared and ready for if it occurs.

5 0
3 years ago
The weather conditions of an area may be expected to change over a(n) _________ period of time.
jenyasd209 [6]

Answer:

Your answer should be 2. Short

Explanation:

4 0
3 years ago
Can You Please Give Me Some Examples of Density-Independent and Density-Dependent Limiting Factors?
ivolga24 [154]
Density-Dependent: 
1<span><span><span><span>. </span>competition.</span><span>   
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7 0
3 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
Hurryyyyy pleaseeeee!!!!!
kolbaska11 [484]

Answer: 2.2x10^4

Explanation: in a adiabatic process pV^y = constant.

So V2=3V1 and p2 = p1 / 3^1.67 = 2.2x10^4 Pa

4 0
3 years ago
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