Question

Find the sixth term of the geometric sequence with a first term of 9 and common ratio of 2

Answer 1

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Answer = 288

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Known

U1 = 9

r = 2

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Question

U6 = ?

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Way to do

$un = a(r {)}^{n - 1}$

$u6= 9(2 {)}^{6 - 1}$

$u6 = 9( {2}^{5} )$

$u6 = 9(32)$

$u6 = 288$

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Notes

• Formula of geometric sequence

$\boxed{\ un = a( {r)}^{n - 1}}$

• Meaning

Un = nth term

a = 1st term

r = ratio

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