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o-na [289]
3 years ago
13

Find the sixth term of the geometric sequence with a first term of 9 and common ratio of 2

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

════════ ∘◦❁◦∘ ════════

<h3>Answer = 288</h3>

════════════════════

<h3>Known</h3>

U1 = 9

r = 2

════════════════════

<h3>Question</h3>

U6 = ?

════════════════════

<h3>Way to do</h3>

un = a(r {)}^{n - 1}

u6= 9(2 {)}^{6 - 1}

u6 = 9( {2}^{5} )

u6 = 9(32)

u6 = 288

════════════════════

<h3>Notes</h3>

• Formula of geometric sequence

\boxed{\  un =  a( {r)}^{n - 1}}

• Meaning

Un = nth term

a = 1st term

r = ratio

════════════════════

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