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3 years ago

12

NEED HELP ASAP ON TIMED TEST!

1 answer:

laiz [17]3 years ago

8 0

Answer:

51.3 degrees

Step-by-step explanation:

Use Trig Ratio to solve for theta aka the angle formed between the ;adder and the ground.

So we have the hypotenuse = 24ft and the adjacent = 15ft so I am going to use the cos ratio.

cos ∅ = a/h

rearrange for theta

∅ = cos -1 ( a/h)

now sub in the information

∅ = 51.3178

now round to the nearest tenth

∅ = 51.3 degrees

write your therefore statement

therefore, the angle between the ladder and the ground is 51.3 degrees.

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8 – (x + 4) = 2<br> determine the value of x in the equation below

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3 years ago

Read 2 more answers

If x = -3 and y = 4x - 1, then y equals what number

Masteriza [31]

$\huge\text{Hey there!}$

$\large\textsf{y = 4x - 1}$

$\large\text{If x= -3, then substitute it into the given equation}$

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3 years ago

Read 2 more answers

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago