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Andrei [34K]
3 years ago
11

Brainliest!! Please help with number 4 and please give me the equation too!! Brainliest!!!

Physics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

Oooo someone is writing a answer. (Also im new to this so Idk what to really do.)

Explanation:

viva [34]3 years ago
4 0

Answer:

3.9×10⁸ m

Explanation:

If x is the distance between the Earth and the Moon, the the light travels a distance of 2x in 2.6 seconds.

Distance = rate × time

2x = (3×10⁸ m/s) (2.6 s)

x = 3.9×10⁸ m

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A circuit is built based on the circuit diagram shown.
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The time needed for a water wave to change from the equilibrium level to the crest is 0.1475 s. What fraction of a wavelength is
dmitriy555 [2]

Answer:

one-fourth of the wavelength

Explanation:

When any wave move form its equilibrium to level to the crest then it covers one-fourth of the wavelength. The waves goes twice to its extreme position, once at the crest and one at the trough.

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3 0
3 years ago
A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywher
Scilla [17]

Answer:

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

Explanation:

The Coulomb's Law gives the force by the charges:

\vec{F} = K\frac{q_1q_2}{r^2}\^r

Let us denote the positon of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F_1 = K\frac{Qq}{x^2 + y^2}\\F_1_x = F_1\cos(\theta)

where Θ is the angle between F_1 and x-axis.

F_1_x = K\frac{Qq}{x^2 + y^2}(\frac{x}{\sqrt{x^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

whereas

F_2_x = K\frac{-Qq}{a^2 + y^2}(-\frac{a}{\sqrt{a^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

Finally, the x-component of the net force is

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

8 0
4 years ago
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