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kkurt [141]
3 years ago
14

On a spaceship designed to support a multiyear voyage to the outer planets of the solar system, plants will be grown to provide

oxygen and to recycle carbon dioxide. Because the spaceship will be so far from the sun, an artificial light source will be needed to support photosynthesis. Which wavelengths of light should be used to maximize plant growth?
Physics
1 answer:
alexira [117]3 years ago
6 0

Answer:

A mixture of blue & red light.

Explanation:

During photosynthesis, the oxygen delivered emanates from water particles and if a weighty isotope of oxygen atom was noticed in delivered sub-atomic oxygen, the water atoms were marked with the hefty isotope.

In order to maximize the growth rate of the plant, the required wavelength of light to be used is a mixture of blue & red light. This is on the grounds that as the absorption optima of plant's photoreceptors are at wavelength frequency of red and blue light, subsequently the combination of red and blue light would be ideal for plant growth and development.

The productivity of red (650–665 nm) LEDs on plant development is straightforward on the grounds that these wavelength frequencies entirely fit with the retention pinnacle of chlorophylls and phytochrome, while the enhanced blue light presented the possibility that development under regular light could be mirrored utilizing blue and red LEDs with negligible use of energy.

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An electron moves along the z-axis with vz=4.1Ã107m/s. As it passes the origin, what are the strength and direction of the magne
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Answer:

a

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive x - axis

b

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive z - axis

Explanation:

From the question we are told that

         The velocity of the electron is v_z = 4.1*10^{7}m/s

Considering the first position

    The equation for the magnetic field is

                    \= B = \frac{\mu_0}{ 4 \pi} \frac{q \=v * \= r}{r^2}

 Now r = \sqrt{i^2 + j^2 + k^2}

  substituting values

           r = \sqrt{1^2 +0^2 +0^2}

              = 1

          \= r = \frac{\r r}{r}

        \r r = 1 i + 0j + 0k

Therefore \= r = \frac{1i + 0j + 0k}{1}

                   = i

So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * i}{1^2}

                 \= B_a=6.56*10^{-19} T (i)

Considering the second  position

    Here

               r = \sqrt{0^2 + 0^2 + 2^2}

                  =2

              \= r = \frac{\r r}{r}

              \r r = 0 i + 0j + 2k

            \= r = \frac{0i + 0j + 2k}{2}

               = k

 So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * k}{1^2}

                 \= B_a=6.56*10^{-19} T (k)

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