Question

If the pOH of vinegar is 9.45, what is its [OH− ]?

Answer 1

Answer:
            [OH⁻]  =  3.54 × 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

                           pOH  =  - log [OH⁻]

Putting value of pOH,

                           9.45  =  -log [OH⁻]

Solving for [OH⁻],

                           [OH⁻]  =  10⁻⁹·⁴⁵                       ∴ 10  =  Antilog

                           [OH⁻]  =  3.54 × 10⁻¹⁰ M

Answer 2

Answer:

3.55 and -10

Explanation: