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lorasvet [3.4K]
3 years ago
11

If the pOH of vinegar is 9.45, what is its [OH− ]?

Chemistry
2 answers:
7nadin3 [17]3 years ago
4 0
Answer:
            [OH⁻]  =  3.54 × 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

                           pOH  =  - log [OH⁻]

Putting value of pOH,

                           9.45  =  -log [OH⁻]

Solving for [OH⁻],

                           [OH⁻]  =  10⁻⁹·⁴⁵                       ∴ 10  =  Antilog

                           [OH⁻]  =  3.54 × 10⁻¹⁰ M
Rainbow [258]3 years ago
3 0

Answer:

3.55 and -10

Explanation:

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