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lorasvet [3.4K]
2 years ago
11

If the pOH of vinegar is 9.45, what is its [OH− ]?

Chemistry
2 answers:
7nadin3 [17]2 years ago
4 0
Answer:
            [OH⁻]  =  3.54 × 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

                           pOH  =  - log [OH⁻]

Putting value of pOH,

                           9.45  =  -log [OH⁻]

Solving for [OH⁻],

                           [OH⁻]  =  10⁻⁹·⁴⁵                       ∴ 10  =  Antilog

                           [OH⁻]  =  3.54 × 10⁻¹⁰ M
Rainbow [258]2 years ago
3 0

Answer:

3.55 and -10

Explanation:

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In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h
LuckyWell [14K]

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 =  $ 32.85

(b) Cost of electricity for 0.025 W  fluorescent  bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

6 0
3 years ago
A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / volume
  • moles = Molarity * volume
  • 0.4293 M * 39.27 mL = 16.86 mmol NaOH

<em>One NaOH moles reacts with one acetic acid mole</em>, so <u>the vinegar sample contains 16.86 mmoles of acetic acid as well</u>.

Finally we <u>calculate the concentration (molarity) of acetic acid</u>:

  • 16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M
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Explanation:

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Answer:

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<h3>Explanation:</h3>

To be lab prepared one must follow these procedures-

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