If the pOH of vinegar is 9.45, what is its [OH− ]?
2 answers:
Answer:
[OH⁻] = 3.54 × 10⁻¹⁰ M
Solution:
pOH is related to [OH⁻] as,
pOH = - log [OH⁻]
Putting value of pOH,
9.45 = -log [OH⁻]
Solving for [OH⁻],
[OH⁻] = 10⁻⁹·⁴⁵ ∴ 10 = Antilog
[OH⁻] = 3.54 × 10⁻¹⁰ M
Answer:
3.55 and -10
Explanation:
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