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lorasvet [3.4K]
3 years ago
11

If the pOH of vinegar is 9.45, what is its [OH− ]?

Chemistry
2 answers:
7nadin3 [17]3 years ago
4 0
Answer:
            [OH⁻]  =  3.54 × 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

                           pOH  =  - log [OH⁻]

Putting value of pOH,

                           9.45  =  -log [OH⁻]

Solving for [OH⁻],

                           [OH⁻]  =  10⁻⁹·⁴⁵                       ∴ 10  =  Antilog

                           [OH⁻]  =  3.54 × 10⁻¹⁰ M
Rainbow [258]3 years ago
3 0

Answer:

3.55 and -10

Explanation:

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What is the maximum amount of ammonia that can be produced when 0.35 mol Nz reacts with 0.90 mol Hz?
professor190 [17]

Answer:

0.6 moles NH₃

Explanation:

The reaction that takes place is:

  • N₂ + 3H₂ → 2NH₃

First we <u>determine the limiting reactant</u>:

  • 0.35 mol N₂ would react completely with (3*0.35) 1.05 moles of H₂. There are not as many H₂ moles, so H₂ is the limiting reactant.

Then we <u>convert H₂ moles (the limiting reactant) to NH₃ moles</u>, keeping in mind the <em>stoichiometry of the reaction</em>:

  • 0.90 mol H₂ * \frac{2molNH_3}{3molH_2}= 0.6 moles NH₃

5 0
3 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
Mention the various ways by which soluble and insoluble salts are prepared
LUCKY_DIMON [66]

Answer:

Explanation:

soluble and insoluble salts are prepared by processes like neutralization reactions, simple displacement reactions and double displacement reactions.

4 0
3 years ago
Describe the appearance of the material. Include its color and state (solid or liquid). Pour ¼ cup of water into a small, clear
Alex777 [14]

<u>Answer:</u>

<em>Here the given material is taken and mixed with water.</em>

<u>Explanation:</u>

The amount of material and water taken are same. Hence if it is not soluble in water it should make a dense and flowy paste like material and if it is soluble in water it should this and thicker density of water should remain.

If the amount of water that we are taking is more than the material will float in water if it is not soluble and lighter than water or would sink if it is heavier than water.

5 0
3 years ago
Read 2 more answers
What characterizes a Homo genesis mixture
Salsk061 [2.6K]

Answer:

The correct answer would be the third choice.

Homo-genesis mixtures are the same in composure, and will be hard to break apart other then with chemical means.

Hope this helps!

6 0
3 years ago
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