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inysia [295]
4 years ago
10

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titra

tion of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH Which statement is most likely to be true?
Chemistry
2 answers:
Goshia [24]4 years ago
8 0

Answer:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

(c) All three titrations have the same pH at their first equivalence point.

The correct anser is (a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

In titration, an equivalent point is the point at which there is enough titrant to react completely with the solution under analysis that is the number of moles and the number of moles of the acid are equal and the compounds in the solution are the produced salt and water

It is the stoichiometric point of the reaction where the number of moles of reactant acid required to neutralize the base is reached which may be in a ratio of acid to base other than 1:1 depending on the stoichiometry of the chemical reaction equation

A weak polyprotoic acid has more than one equivalence point depending on the number of ionized hydrogen ions that can react with the base in the titration

Thus the 25ml titration of sodium hydroxide solution consists of \frac{25}{1000} × 0.1 ,oles of NaOH = 0.0025mols of NaOH which gives

NaOH(aq)→ Na^{+} (aq) + OH^{-}(aq) which consists of one mole of Positive sodium ion and one mole of negatively charged hydroxide ion OH^{-} available for reaction with an hydrogen ion hence all three titrations require the same volume of NaOH to reach their first equivalence point.

Setler79 [48]4 years ago
6 0

Complete Question:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

(c) All three titrations have the same pH at their first equivalence point.

Answer:

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

(i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

                     

(iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

Therefore, all the acids require the same number of moles of NaOH to reach their first equivalence points

Note that the concentration of the base NaOH are also the same, therefore the volume of NaOH required to reach equivalence point would also be the same for all the three titrations.

All three titrations don't have the same initial and equivalence point pH because they all have different acidic properties.

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For this problem we just need to remember the equation and that the volume is always in liters: MaVa=MbVb

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  Second step: Molarity equation

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For the third problem, you will just use the same equation as the first: MaVa= MbVb

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  0.57 M * x L= 0.875 M * 0.02383 L

With this equation, we want to find the moles of NaOH by using the molarity equation first then because MaVa= MbVb, we know that the number of moles has to be equal.

   0.75 M= x mol/ 0.0227 L    mol NaOH = 0.75 M *0.0227 L         mol NaOH= 0.017025

  So next, we can set it to the mass of the acid using this equation: Molar Mass= mass/ moles

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 And with that you will find the molar mass of HX, and even determine what X is.

Explanation:

hope I helped

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