1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inysia [295]
3 years ago
10

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titra

tion of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH Which statement is most likely to be true?
Chemistry
2 answers:
Goshia [24]3 years ago
8 0

Answer:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

(c) All three titrations have the same pH at their first equivalence point.

The correct anser is (a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

In titration, an equivalent point is the point at which there is enough titrant to react completely with the solution under analysis that is the number of moles and the number of moles of the acid are equal and the compounds in the solution are the produced salt and water

It is the stoichiometric point of the reaction where the number of moles of reactant acid required to neutralize the base is reached which may be in a ratio of acid to base other than 1:1 depending on the stoichiometry of the chemical reaction equation

A weak polyprotoic acid has more than one equivalence point depending on the number of ionized hydrogen ions that can react with the base in the titration

Thus the 25ml titration of sodium hydroxide solution consists of \frac{25}{1000} × 0.1 ,oles of NaOH = 0.0025mols of NaOH which gives

NaOH(aq)→ Na^{+} (aq) + OH^{-}(aq) which consists of one mole of Positive sodium ion and one mole of negatively charged hydroxide ion OH^{-} available for reaction with an hydrogen ion hence all three titrations require the same volume of NaOH to reach their first equivalence point.

Setler79 [48]3 years ago
6 0

Complete Question:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

(c) All three titrations have the same pH at their first equivalence point.

Answer:

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

(i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

                     

(iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH

number of moles of acid = \frac{25}{1000} dm^{3}  * 0.1 M = 0.0025 moles

Therefore, all the acids require the same number of moles of NaOH to reach their first equivalence points

Note that the concentration of the base NaOH are also the same, therefore the volume of NaOH required to reach equivalence point would also be the same for all the three titrations.

All three titrations don't have the same initial and equivalence point pH because they all have different acidic properties.

You might be interested in
Help!!!!please i need to get this done before 3pm!today
Lunna [17]
4. 2 miles/ hour
5. 80 hours
6. 408 miles
7. a) 0
b) 500 N [right]
c) 200 N [left]

I don’t know what it meant by resultant force, but i think it’s basically the same as net force.

Hope this helps!!

3 0
2 years ago
For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min
abruzzese [7]

Answer:

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

V = V_{max}\times \frac{[S]}{ (Km + [S])}

V_{max }=k_{cat}\times E_o

Where  :

V_{max} = max rate velocity

[S] = substrate concentration

K_m = Michaelis-Menten constant

V = reaction rate

k_{cat} = catalytic rate constant

E_o = initial enzyme concentration

We have :

K_m=10.0mM

E_o=10.0\mu M=10.0\times 0.001 mM

V_{max}=0.172 mM/min

V_{max} is the rate is obtained when all enzyme is bonded to the substrate. k_{cat} is termed as the turnover number.

k_{cat}=\frac{V_{max}}{E_o}=\frac{0.172 mM}{10.0\times 0.001 mM}

=17.2 minutes

17.2 minutes is the value of the turnover number.

3 0
3 years ago
If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a
strojnjashka [21]

Answer : The final temperature of the mixture is, 22.14^oC

Explanation :

First we have to calculate the mass of ethanol and water.

\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g

and,

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ethanol = 2.42J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol = 35.5 g

m_2 = mass of water = 45.0 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 8.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get:

35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.14^oC

Therefore, the final temperature of the mixture is, 22.14^oC

3 0
3 years ago
Explain how plate tectonics are responsible for where we find some of our natural resources.
Mekhanik [1.2K]
At divergent boundaries, plates separate, forming a narrow rift valley. Here, geysers spurt super-heated water, and magma, or molten rock, rises from the mantle and solidifies into basalt, forming new crust. Thus, at divergent boundaries, oceanic crust is created.
6 0
3 years ago
Read 2 more answers
Look at the following reaction. How could you increase the production of 2NH3(g)? N2(g) + 3H2(g) 2NH3(g) Increase the volume of
Zolol [24]
The correct option is B. To increase the production of ammonia, you have to increase the pressure of the system. Increase in pressure will result in increased production of ammonia because this will drive the chemical reaction forward.
5 0
3 years ago
Read 2 more answers
Other questions:
  • Show a sample for calculating frequency from wavelength​
    12·1 answer
  • While David was riding his bike around the circular cul-de-sac by his house he wondered if the constant circle motion was having
    11·1 answer
  • What is the percent composition of potassium in KNO3
    5·2 answers
  • A drop of water placed on a smooth, dry surface will form a dome-shaped droplet instead of flowing outward in different directio
    5·2 answers
  • A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 0.300 atm at 20.0°C. The round part of the tan
    6·1 answer
  • What is concentrated salt solution added to the tube with the cheek cells? ​
    5·1 answer
  • How is stoichiometry used to calculate amount of product from amount of reactant?
    15·1 answer
  • What is the percent yield of either if 1.11L(d=0.7134 g/mL) is isolated from the reaction of 1.500L of C2H5OH
    5·1 answer
  • Where are all metalloid found in this periodic table?
    13·2 answers
  • If 167 cm2 of leather is stitched together to make a baseball, what is the radius of the baseball?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!