Question

Consider the decomposition of hydrogen peroxide reaction. If the rate of decomposition of hydrogen peroxide at a particular temperature is determined to be 0.098 mol/(L·s), what are the rates of reaction with respect to the products of the decomposition reaction?

Answer 1

Answer:

0.049 mol/L.s

Explanation:

The decomposition of hydrogen peroxide is:

$H_2O_2 \to H_2O + \dfrac{1}{2}O_2$

$Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}$

The rate of decomposition reaction = the rate of formation of $H_2O$ = 0.098 mol/L.s

∴

Rate of formation of $O_2$ $= \dfrac{ rate \ of \ reaction }{2}$

$= \dfrac{ 0.098 }{2}$

= 0.049 mol/L.s