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enot [183]
3 years ago
15

Consider the decomposition of hydrogen peroxide reaction. If the rate of decomposition of hydrogen peroxide at a particular temp

erature is determined to be 0.098 mol/(L·s), what are the rates of reaction with respect to the products of the decomposition reaction?
Chemistry
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer:

0.049 mol/L.s

Explanation:

The decomposition of hydrogen peroxide is:

H_2O_2 \to H_2O + \dfrac{1}{2}O_2

Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2  \Delta [H_2O_2]}{\Delta t}

The rate of decomposition reaction = the rate of formation of H_2O = 0.098 mol/L.s

∴

Rate of formation of O_2 = \dfrac{ rate \ of \ reaction }{2}

= \dfrac{ 0.098 }{2}

= 0.049 mol/L.s

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