Phenol red is used as the indicator for the Urea Medium because the indicator detects the formation of ammonia caused by the hydrolysis of urea done by the bacteria. Bromothymol blue is used in Simmons Citrate Agar because it effectively indicates the formation of carbonates formed by the consumption of citrate.
Answer:
chromoblastomycosis
Explanation:
Here is the complete question;. A sample of the tissue from an inflamed, pus-filled area on the lower leg is treated with KOH and stained with GMS. Under the microscope golden brown spheres are visible. What disease are these observations consistent with?
A) pityriasis
B) fungemia
C) chromoblastomycosis
D) mycetoma
E) sporotrichosis
Answer is
C) chromoblastomycosis
Chromoblastomycosis is a chronic fungal infection of the skin and the subcutaneous tissue caused by traumatic inoculation of a specific group of dematiaceous fungi (usually Fonsecaea pedrosoi, Phialophora verrucosa, Cladosporium carrionii, or Fonsecaea compacta) through the skin.
It's empty or fairly large, making the sounds from your hands bounce of the walls and therefore having it echo
Answer:
The effect would be that the green leaves, which contain chloroplasts, containing a chemical called chlorophyll would enable the plants to take in more energy in the form of sunlight, enabling the plants to photosynthesise and grow.
Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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