I NEED HELP! I AM THE WORST AT MATH

A right triangle ABC with height AB labeled 3 units and base BC labeled 5 units is shown. The area of the triangle above will eq

zhenek [66]

Answer:

Step-by-step explanation:

Answer:

w=3

Step-by-step explanation:

The area of the triangle is given by

A = 1/2 bh

the base is 5 and the height is 3

A = 1/2 (3) * 5 = 15/2 units ^2

The area of a rectangle is

A = l*w

A = 5w

The area of the triangle = 1/2 the area of the rectangle

15/2 = 1/2 *5w

15/2 = 5/2 w

Multiply each side by 2/5 to isolate w

2/5 * 15/2 = 2/5 *5/2 w

3 =w

Read more on Brainly.com - brainly.com/question/11938580#readmore

5 0

3 years ago

Please answer All!!! (first part)

goblinko [34]

3.
-0.5(-4) +1= 2+1 =3
-0.5(-2)+ 1= 1+1 = 2
-0.5(0) + 1 = 1
-0.5(2) + 1 = -1 + 1 = 0
-0.5(4) + 1 = -2+1 = -1
The answers follow left to right

5.
Y=1
Y=-1
Y= 1
Y= 3
Y= 7
This answer also I ordered

4 0

3 years ago

Isotope ⁷⁹br has an abundance of 50.69%

Simora [160]

Answer:

79.986

Step-by-step explanation:

Let A represent isotope ⁷⁹Br

Let B represent isotope ⁸¹Br

From the question given above, the following data were obtained:

For Isotope A (⁷⁹Br):

Mass of A = 79

Abundance of A (A%) = 50.69%

For isotope B (⁸¹Br):

Mass of B = 81

Abundance of B (B%) = 49.31%

Relative atomic mass of Br =?

The relative atomic mass (RAM) of Br can be obtained as follow:

RAM = [(Mass of A × A%) /100] + [(Mass of B × B%) /100]

= [(79 × 50.69) /100] + [(81 × 49.31) /100]

= 40.0451 + 39.9411

= 79.986 amu

Thus, the relative atomic mass of Br is 79.986

5 0

3 years ago

The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates

tatyana61 [14]

Answer:

There will be no change in C and D but E must increase.

Step-by-step explanation:

We are given a equation of circle as:

$x^2+y^2+Cx+Dy+E = 0$

it could also be represented in general form of equation of circle as:

$(x+\dfrac{C}{2})^2+(y+\dfrac{D}{2})^2=\dfrac{C^2}{4}+\dfrac{D^2}{4}-E$

( since we add both the side of the equality by $\dfrac{C^2}{4}$ and $\dfrac{D^2}{4}$ )

Hence, on comparing the equation with general form of the equation:

$(x-g)^2+(y-h)^2=r^2$

The center of circle is (g,h) and radius is r.

Here we have the center as:

$(\dfrac{-C}{2},\dfrac{-D}{2})$

and radius is given aS:

$r=\sqrt{\dfrac{C^2}{4}+\dfrac{D^2}{4}-E}\\\\r=\sqrt{\dfrac{C^2+D^2-4E}{4}$

$r=\dfrac{\sqrt{C^2+D^2-4E}}{2}$

As there is no change in the center hence the value of $\dfrac{-C}{2}$ and $\dfrac{-D}{2}$ remains unchanged i.e. the value of C and D remains unchanged.

Now we are given that the radius of the circle is decreased.

that means the change in radius is due to the change in E.

Hence for the quantity $r=\dfrac{\sqrt{C^2+D^2-4E}}{2}\\$ to decrease E must increase so that the total quantity decreases.

Hence there will be no change in C and D but E must increase in order to decrease the radius of circle.

6 0

3 years ago

Read 2 more answers

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The pr

lyudmila [28]

Well.... If you already know that the probabilities of landing on red or blue is 9 and 6 over 20, just add them together and you should get 15/20. Now you know that there is only 5/20 left over. SO 5 over 20 is your answer. Hope that helps.

4 0

3 years ago

Read 2 more answers