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3 years ago

Erosion and physical weathering is a ________________ force that affects land formation

Physics

1 answer:

bearhunter [10]3 years ago

7 0

Answer:

Any choices for the blank?

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A 3.5-cm radius hemisphere contains a total charge of 6.6 × 10–7

spayn [35]

As per Gauss Law

Net flux through enclosed surface is

$\phi = \frac{Q}{\epsilon_0}$

here through this hemisphere total flux will pass through two portions

1). from the curved surface

2). from flat circular base

so now we have

$\phi_{base} + \phi_{surface} = \frac{Q}{\epsilon_0}$

given that

$Q = 6.6 * 10^{-7} C$

$\phi_{surface} = 9.8 * 10^4$

now we have

$\phi_{base} + 9.8*10^4 = \frac{6.6*10^7}{8.85 * 10^{-12}}$

$\phi_{base} = - 9.8 *10^4 + 7.46 * 10^4$

$\phi_{base} = - 2.34 * 10^4 N*m^2/C$

4 0

3 years ago

If the density of an object is 30 g/cm3 and its volume is 10 cm3, what is its mass in grams?

Inga [223]

Density = Mass / Volume

Mass = Density * Volume

Mass = 30 g/cm³ * 10 cm³ = 300 g

Mass = 300 g

7 0

3 years ago

You toss a rock of mass mm vertically upward. Air resistance can be neglected. The rock reaches a maximum height hh above your h

skad [1K]

Answer:

The speed of the rock when it is at height h/4 is $\dfrac{\sqrt{3gh} }{2}$ .

Explanation:

At maximum height the final velocity of the rock is equal to 0. Let u is the initial velocity of the rock. Using the conservation of energy to find it as :

$u^2=2gh$ .......(1)

We need to find the speed of the rock when it is at height h/4. Let v' is the speed. Using 3rd equation of motion as :

$v'^2=u^2+2as$

here a = -g and s = h/4

$v'^2=u^2-2g\times \dfrac{h}{4}$

Using equation (1) :

$v'^2=(2gh)-2g\times \dfrac{h}{4}\\\\v'^2=\dfrac{3gh}{4}\\\\v'=\dfrac{\sqrt{3gh} }{2}$

So, the speed of the rock when it is at height h/4 is $\dfrac{\sqrt{3gh} }{2}$ . Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

A blender takes in 180 J of electrical energy. Of the 180 J, 90 J are transformed into kinetic energy, 60 J are transformed into

a_sh-v [17]

Fa sho it's 30j edge said so

6 0

3 years ago

Read 2 more answers

A capacitor is charged to a potential difference of 3 volt it delivers 30% store energy to lamp what is the final potential diff

nexus9112 [7]

Answer:

3.98V

Explanation:

Given

Pontential difference V as 3v

Energy delivered is 30%,

Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)

So E=V^2

E=3^2=9

At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3

But E=V^2

✓E=V

✓6.3=3.98V

4 0

3 years ago