Answer:
I would love to help, Could you put the question in English?
Explanation:
Answer:
1.2 amps :)
Explanation:
A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?
Known:
Unknown:
I = V/R
= 12.0 V / 10.0 Ω
= 1.2 amps
Answer:
a. 2143 turns/m
b. 111.5 m
Explanation:
a. The minimum number of turns per unit length (N/L) can be found using the following equation:
![B = \frac{\mu_{0}NI}{L}](https://tex.z-dn.net/?f=%20B%20%3D%20%5Cfrac%7B%5Cmu_%7B0%7DNI%7D%7BL%7D%20)
![\frac{N}{L} = \frac{B}{\mu_{0}I} = \frac{3.50 \cdot 10^{-2} T}{4\pi \cdot 10^{-7} Tm/A*13.0 A} = 2143 turns/m](https://tex.z-dn.net/?f=%20%5Cfrac%7BN%7D%7BL%7D%20%3D%20%5Cfrac%7BB%7D%7B%5Cmu_%7B0%7DI%7D%20%3D%20%5Cfrac%7B3.50%20%5Ccdot%2010%5E%7B-2%7D%20T%7D%7B4%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%20Tm%2FA%2A13.0%20A%7D%20%3D%202143%20turns%2Fm%20)
Hence, the minimum number of turns per unit length is 2143 turns/m.
b. The total length of wire is the following:
![N = 2143 turns/m*L = 2143 turns/m*46.0 \cdot 10^{-2} m = 986 turns](https://tex.z-dn.net/?f=%20N%20%3D%202143%20turns%2Fm%2AL%20%3D%202143%20turns%2Fm%2A46.0%20%5Ccdot%2010%5E%7B-2%7D%20m%20%3D%20986%20turns%20)
Since each turn has length 2πr of wire, the total length is:
![L_{T} = N*2\pi r = 986 turn*2*\pi*1.80 \cdot 10^{-2} m = 111.5 m](https://tex.z-dn.net/?f=%20L_%7BT%7D%20%3D%20N%2A2%5Cpi%20r%20%3D%20986%20turn%2A2%2A%5Cpi%2A1.80%20%5Ccdot%2010%5E%7B-2%7D%20m%20%3D%20111.5%20m%20)
Therefore, the total length of wire required is 111.5 m.
I hope it helps you!
Become more positive instead of negative