crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied
1 answer:
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Answer:6.71 m/s
Explanation:
Given
Apple fall from a height of
We need to find the impact speed of apple which can be given by using
where v=final velocity
u=initial velocity
h=Displacement
Assuming initial velocity to be zero
substituting the value we get
Answer:
The percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%
Explanation:
Mechanical energy (Potential energy, PE) of the oscillator is calculated as;
PE = ¹/₂KA²
During the first oscillation;
PE₁ = ¹/₂KA₁²
During the second oscillation;
A₂ = A₁ - 0.0342A₁ = 0.9658A₁
PE₂ = ¹/₂KA₂²
PE₂ = ¹/₂K (0.9658A₁)²
PE₂ = (0.9658²)¹/₂KA₁²
PE₂ = (0.9328)¹/₂KA₁²
PE₂ = 0.9328PE₁
Percentage of the mechanical energy of the oscillator lost in each cycle;
Therefore, the percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%