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2 years ago

crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied

Physics

1 answer:

Klio2033 [76]2 years ago

4 0

Answer:

F = 5226.6 N

Explanation:

To solve a lever, the rotational equilibrium relation must be used.

We place the reference system on the fulcrum (pivot point) and assume that the positive direction is counterclockwise

F d₁ = W d₂

where F is the applied force, W is the weight to be lifted, d₁ and d₂ are the distances from the fulcrum.

In this case the length of the lever is L = 5m, t the distance desired by the fulcrum from the weight to be lifted is

d₂ = 200 cm = 2 m

therefore the distance to the applied force is

d₁ = L -d₂

d₁ = 5 -2

d₁= 3m

we clear from the equation

F = W d₂ / d₁

W = m g

F = m g d₂ / d₁

we calculate

F = 800 9.8 2/3

F = 5226.6 N

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So, mg $h_o$ = $\frac{1}{2}$ kx² - mgx

And, $h_o$ = ( $\frac{1}{2}$ kx² - mgx )/(mg) = $[\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)$ ]/(0.645x9.8)

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2 years ago

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Answer: 5 seconds

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3 years ago

crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied​

crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied