The answer is A study of different surfaces to compare ability to repel water. Hope this helps!
Answer:
Push and pull are both forces, but the difference is in their direction at which it is applied. If the force applied in the direction of motion of the particle then we call it push. If that force applied in the direction OPPOSITE to the motion of the particle then it it termed as pull
Answer:
v = 5.88 10⁷ m / s
Explanation:
For this exercise we use the relation
E = m c²
also indicate that all energy is converted into kinetic energy
E = K = ½ (M-2m) v²
where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined
we substitute
m c² = ½ (M-2m) v²
v² = 
let's calculate
v = 
v = 
v = 5.88 10⁷ m / s
It accelerates from rest at 1.1 m/s^2 for 20s.
<span>s = at^2/2 </span>
<span>s = (.5)(1.1)(20)^2= 220m </span>
<span>then it travels 1100m </span>
<span>Then it slows down at 2.2m/s^2 until it stops at the station. </span>
<span>Calculate the train's speed: </span>
<span>v = at </span>
<span>v = (1.1)(20) = 22m/s
</span>
<span>Now, calculate the time to stop: </span>
<span>v = at </span>
<span>t = 22/2.2 = 10s </span>
<span>s = t(u+v)/2 </span>
<span>s = 10(0+22)/2 = 110m </span>
<span>(A) Total distance = 220 +1100+110 = 1430m </span>
<span>(B) Time = 20 + 1100/22 + 10 = 80s</span>
