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Nookie1986 [14]
3 years ago
15

What are the function of mercury barometer ​

Physics
2 answers:
Orlov [11]3 years ago
3 0

Answer:

A mercury barometer is an instrument used to measure atmospheric pressure in a certain location and has a vertical glass tube closed at the top sitting in an open mercury-filled basin at the bottom. Mercury in the tube adjusts until the weight of it balances the atmospheric force exerted on the reservoir.

Explanation:

olganol [36]3 years ago
3 0

Answer:

1. The density of mercury (=13.6×10 to power 3 kg /m) is greater than that of any other liquid so only 0.76m height of mercury column is needed to balance the normal atmospheric pressure. Use of other liquids require much longer tube .

2.The vapour pressure of mercury is negligible, and so the vacuum does not affect the barometric height.

3.The mercury neither wets nor sticks to the glass tube therefore gives accurate reading.

4.It can easily be obtained in a pure taste .

5. Mercury has a opaque and shinning surface therefore can me easily seen while taking the reading.

Explanation:

A mercury barometer is an instrument used to measure atmospheric pressure in a certain location and has a vertical glass tube closed at the top sitting in an open mercury-filled basin at the bottom. Mercury in the tube adjusts until the weight of it balances the atmospheric force exerted on the reservoir.

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Si se aplica una fuerza de 3n sobre un sistema se genera 15000 cal de calor generandose a su vez un trabajo de 300 j ¿en cuanto
Marizza181 [45]

Answer: +/- 71,65 Calorías

Explanation: Se deduce que la fuerza aplica para aumentar o disminuir la energía del generador.

+/- x Calorías

X = Equivalente de 300 Joules en calorías

Para poder pasar Joules a calorías.

Hacemos una regla de 3 simple

1 Calorías = 4,18 Julios

0,2392 calorías = 1 Julio

(  1 / 4,18 = 0,2392 calorías)

300 Julios = 71,65 calorías

(0,2392 calorías x 300 julios = +/- 71,65 calorías)

5 0
3 years ago
The force between two interacting charges is 9.0 × 10-5 newtons. They are kept 1 meter apart. If the magnitude of one charge is
Oliga [24]

The magnitude of other charge will be 1 × 10⁻² coulomb

The formula of electrostatic force is

Electrostatic force = K q1 q1 / r²

where k is the coulomb's constant whose value is 9 × 10⁹

q1 and a2 are the magnitude of charges

and r is the distance between them

magnitude of the force given to us is 9.0 × 10⁻⁵ newtons

magnitude of one charge = 1.0 × 10⁻⁶ coulomb

Force = K q1 q2 / r²

9.0 × 10⁻⁵ = ( ( 9 × 10⁹ ) × ( 1.0 × 10⁻⁶ ) × q2 ) / 1

9.0 × 10⁻⁵ =  9 × 10³ × q2  

10⁻² = q2  

Charge on q2 is 1 × 10⁻² coulomb

So the magnitude of the second charge is came out to be 1 × 10⁻² coulomb after applying the formula of electrostatic force.

Learn more about electrostatic force here:

brainly.com/question/17692887

#SPJ10

8 0
3 years ago
A mole is defined as the number of atoms in an exact mass of which isotope?
alisha [4.7K]

Answer:

Isotope of carbon-12.

Explanation:

The MOLE  is a unit of measurement of the amount of a pure substance which contains exactly the same number of chemical units which could be (Atoms, molecules etc.) posses atoms in exactly 12 grams of isotope of carbon-12 (i.e., 6.022\times 10^{23}).

So, The mole is the Notation  used for an amount 6.022\times 10^{23}  as same the 12 number is used for dozen for making count of Bananas and many more.

The 6.022\times 10^{23} is known as the fundamental constant names Avogadro's number (N_{A}), It is in the honor of Italian scientist Amedeo Avogadro.

7 0
3 years ago
When one form of energy is converted into another what is the name of that
Svetradugi [14.3K]
Transformation of energy, because energy cannot be created or destroyed
8 0
3 years ago
What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?
Vitek1552 [10]

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

P.E = \frac {1}{2}kx^{2}

Substituting into the equation, we have;

P.E = \frac {1}{2}*71.8 *(0.35)^{2}

P.E = 35.9 * 0.1225

Elastic potential energy = 4.398 Joules.

<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

3 0
3 years ago
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