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iren2701 [21]
2 years ago
15

The electrical voltage between the ends of a resistor is equal to 8 V. A student has two voltmeters available that measure up to

6 V. The voltages of the voltmeters are equal to 500 ohms and 600 ohms, respectively. What voltages will the connected voltmeters indicate? (Fig. 3.45)​

Physics
1 answer:
Rufina [12.5K]2 years ago
6 0

Answer:

I = V / R

I1 = 6 / 500 = .012   amps for full scale deflection

I2 = 6 / 600 = .01   amps for full scale deflection

I = 8 / 1100 = .00727   amps thru load (actual current)

D1 = .00727 / .012 = .606 of full scale deflection

D2 = .00727 / .01 = .727    of full scale deflection

V1 = .606 * 6 = 3.64 V  (of 6 V)

V2 = .727 * 6 = 4.36 V   (of 6 V)

Check: V1 + V2 = 3.64 + 4.36 = 8 V

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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
notka56 [123]

Answer:

A,)FD= 114.1N

B)Torque=798.5Nm

Explanation:

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m^2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)

If the wind blows at 6.5 m/s, what is the magnitude of the drag force of the wind on the canopy? Assume a drag coefficient of 0.50 and the density of air of 1.2 kg/m^3

B)What torque does this force exert on the tree, measured about the point where the trunk meets the ground?

A)The equation of Drag force equation can be expressed below,

FD =[ CD × A × ρ × (v^2/ 2)]

Where CD= Drag coefficient for cone-shape = 0.5

ρ = Density

Area of of the tree canopy = 9.0 m^2

density of air of = 1.2 kg/m^3

V= wind velocity= 6.5 m/s,

If we substitute those values to the equation, we have;

FD =[ CD × A × ρ × (v^2/ 2)]

F= [ 0.5 × 9.0 m^2 × 1.2 kg/m^3 ( 6.5 m/s/ 2)]

FD= 114.1N

B) the torque can be calculated using below formula below

Torque= (Force × distance)

= 114.1 × 7

= 798.5Nm

8 0
3 years ago
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