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iren2701 [21]
2 years ago
15

The electrical voltage between the ends of a resistor is equal to 8 V. A student has two voltmeters available that measure up to

6 V. The voltages of the voltmeters are equal to 500 ohms and 600 ohms, respectively. What voltages will the connected voltmeters indicate? (Fig. 3.45)​

Physics
1 answer:
Rufina [12.5K]2 years ago
6 0

Answer:

I = V / R

I1 = 6 / 500 = .012   amps for full scale deflection

I2 = 6 / 600 = .01   amps for full scale deflection

I = 8 / 1100 = .00727   amps thru load (actual current)

D1 = .00727 / .012 = .606 of full scale deflection

D2 = .00727 / .01 = .727    of full scale deflection

V1 = .606 * 6 = 3.64 V  (of 6 V)

V2 = .727 * 6 = 4.36 V   (of 6 V)

Check: V1 + V2 = 3.64 + 4.36 = 8 V

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Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

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which of these best dscribes Earth's mantle? A. most dense layer, consists of the outer and inner parts B. thinnest under the oc
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C. middle layer, density increases with depth as pressure increases

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If a liquid is heated and the temperature at which it boils is measured, the _____ property is being measured.
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5 0
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Read 2 more answers
An object is 70 um long and 47.66um wide. how long and wide is the object in km?​
Ganezh [65]

Answer:

length =  7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

1km = 1*10^3 m

or

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

1 μm = 1*10^(-6 - 3)km

1 μm = 1*10^(-9)km

Now with this relationship we can transform our measures:

Length: 70 μm is 70 times 1*10^(-9)km, or:

L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

W = 46.66*1*10^(-9)km = 4.666*10^(-8) km

7 0
2 years ago
Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a
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Answer:

Maximum speed of the car is 17.37 m/s.

Explanation:

Given that,

Radius of the circular track, r = 79 m

The coefficient of friction, \mu=0.39

To find,

The maximum speed of car.

Solution,

Let v is the maximum speed of the car at which it can safely travel. It can be calculated by balancing the centripetal force and the gravitational force acting on it as :

v=\sqrt{\mu rg}

v=\sqrt{0.39\times 79\times 9.8}

v = 17.37 m/s

So, the maximum speed of the car is 17.37 m/s.

6 0
3 years ago
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