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3 years ago

Which of the following would be an atom of Gold (AU)? *

Physics

1 answer:

Rus_ich [418]3 years ago

5 0

Answer:

Explanation:

well! a and d are out of topics because proton and electron must be same so do the answer c and d are differ in neutron so u can find it by subtracting mass to atomic number have a nice day !

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A 200 kg object accelerate at a rate of 5.5m/s2. Calculate the force required to produce this acceleration.

Lilit [14]

Answer:

F = 1100 Newtons

Explanation:

8 0

3 years ago

HELP ASAP 70 POINTS BRAINLIST What type of symbiotic relationship is reflected between the Druid Wolfpack and the Elk in the Yel

DerKrebs [107]

Answer: they are both animals and they live near the yellow stone volcano so basically if the volcano erupts they'll be the first to die.

Explanation:

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3 years ago

In this image of a pendulum, where is the lowest potential energy found?

uranmaximum [27]

Think about the formula for potential energy. (Surely you remember it):

Potential energy = (mass) x (acceleration of gravity) x (height)

-- The mass on the end of the pendulum doesn't change.

-- The acceleration of gravity doesn't change.

-- The only thing that changes is the height of the mass on the end.

So the potential energy is lowest when its height is the lowest.

That's position <em>B </em>.

4 0

3 years ago

Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf

Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = $1100^{\circ}C$

Surface concentration of arsenic, $C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}$

Surface concentration below Silicon surface, $C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}$

D = $3.0\times 10^{- 14}\ cm^{2}/s$

x = $1.2\mu m = 1.2\times 10^{- 4}\ cm$

Initial concentration at t = 0, $C_{o} = 0$

Now, by using Flick's second eqn:

$\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})$

Thus by putting appropriate values:

$\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})$

$0.997 = erf(\frac{364.4}{\sqrt{t}})$ (1)

Now,

$erf(z) = 0.997$

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

$\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}$

z = 2.12

Now, using eqn (1) and above value:

$\frac{364.4}{\sqrt{t}} = 2.12$

$t = (\frac{364.4}{2.12})^{2}$ = 26700 s

t = $\frac{26700}{3600} = 7.42\ h$

7 0

3 years ago

Samuel places a ladder against his house. The base of the

NemiM [27]

Answer:

d. 8 feet

Explanation:

(height)^2 = (10)^2 - (6)^2

= 100 - 36

height = √64

= 8 feet

5 0

3 years ago

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