Answer:
Step-by-step explanation:
4 over 5 = 4/5
First, multiply 20 to both numerator and denominator:
(4/5)(20/20) = 80/100
Next, change the fraction into a decimal. move the decimal sign to the left two place values (and drop the denominator)
80/100 = 0.80
Next, to change the decimal to a percentage, move the decimal point to the right two place value and add the % sign.
0.80 = 80%
80% is your answer
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Answer:
W= 5.744
Step-by-step explanation:
given that a grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a standard deviation of 1.4 ounces
Sample size n= 49
Margin of error = 0.10 (10% risk )
Let us assume X no of apples having mean weight of 6 oz is N(6,1.4)
Then sample mean will be normal with (6, 1.4/7) = (6,0.2)
(Because sample mean follows normal with std error as std dev /sqrt of sample size)
Now required probability <0.10
i.e.
Since x bar is normal we find z score for
From std normal distribution table we find that z = 1.28
Corresponding X score =
In fact, this problem belongs to the chemistry section. Recall that many other sciences require mathematical calculations. The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.
Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute. Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.
The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g. Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
