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3 years ago

Jack jogged 15 miles in 3 hours. If he ran at a

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

Answer:

15 miles= 3 hours

x = 2.5

37.5/3= 3x/3

12.5 miles = x

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Please answer quick!!

rewona [7]

Answer: B

Step-by-step explanation:

$\frac{2}{7k}(k-7)$

$\frac{2k-14}{7k}$

$\frac{2k}{7k}-\frac{14}{7k}$

$\frac{2}{7}-\frac{2}{k}$

7 0

3 years ago

Suppose that the handedness of the last fifteen U.S. presidents is as follows:40% were left-handed (L)47% were Democrats (D)If a

lesantik [10]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Probability that they were left handed P(L)= 40%

Probability that they were Democrats P(D)= 47%

So, P(L∩D) = 135 = 0.13

Now, to check whether they are independent or not.

We will find P(L) × P(D) is given by

$P(L)\times P(D)=0.47\times 0.40=0.188$

Since P(L) . P(D) ≠ P(L∩D)

So, they are not independent.

Hence, Option 'c' is correct.

3 0

4 years ago

A large carton of milk is 72 ounces. How

agasfer [191]

Answer: not here!

Step-by-step explanation: 72 ounces is 9 cups! (Divide by 8) (Assuming you mean US cups)

6 0

3 years ago

Read 2 more answers

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

3 years ago

Someone please help me

Karolina [17]

Answer:

them some expensive pencils

8 0

3 years ago