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Ber [7]
3 years ago
11

The length of the base of the triangle is 78 mm and the height is 55 mm. Find the area.

Mathematics
1 answer:
leva [86]3 years ago
6 0

Answer: 2145 ²

Step-by-step explanation:

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Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC. Then list the s
Allisa [31]

For line B to AC:  y - 6 = (1/3)(x - 4);  y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14

For line A to BC:  y - 6 = (-1)(x - 0);  y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

(3y - x = 14) + (y + x = 6) =>  4y = 20, y = +5;  Substitute this into y + x = 6:  5 + x = 6, x = +1

<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>

5 0
3 years ago
Solve for x Enter the solution from least to greatest (x+6)(-x+1)=0
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

x + 6 = 0

x = -6

-x + 1 = 0

-x = -1

x = 1

x = -6, 1

3 0
3 years ago
Please I need help!! Thank you
Artemon [7]
BD=10 because it is symmetrical to AD.
6 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
Idk how to solve this exponent problem ?
Wewaii [24]

Answer:256

Step-by-step explanation:To divide power of the same base,subtract the denominator's exponent.Subtract 4 from 7 to get 4.Then calculate 4 to the power of 4 and get 256

8 0
3 years ago
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