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3 years ago

This table lists the densities of four different substances.

Physics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

GREATER than 1 g/cm. 3, it will SINK in water. LESS than 1 g/cm3, it will FLOAT in water. If an object's density is: Density of Object > Density of Liquid.

Explanation:

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What types of EM waves have you seen or used today? Describe them.

Mrrafil [7]

Answer:

none

Explanation:

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3 years ago

Read 2 more answers

Give two examples of contact force and non contact force

Crank

Answer:

Explanation:

The two examples of contact forces are frictional force and applied force. The two examples of noncontact forces are gravitational force and magnetic force.

5 0

2 years ago

Si tu velocidad al caminar es 0,3 m/s. Determina el tiempo que demorarias en llegar al sol en horas (REALIZAR TRANSFORMACIÓN DE

Contact [7]

Answer:

138,516,546.9 horas.

Explanation:

Tenemos que usar la ecuación:

Velocidad = distancia/tiempo

Acá tenemos:

Velocidad = 0.3m/s

distancia = 149597870700 m

y queremos resolver la ecuación para el tiempo:

0.3m/s = 149597870700m/tiempo.

tiempo = 149597870700m/(0.3m/s) = 498,659,569,000 s

y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:

498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.

6 0

3 years ago

The position function of a particle is given by s=2t3−3t2−63t,t⩾0.s=2t3−3t2−63t,t⩾0. where ss is measured in meters and tt in se

Kisachek [45]

Answer:

$t=5.72\ s$

Explanation:

Given:

the displacement as the function of time:

$s=2t^3-3t^2-63t$

here time is in seconds and the displacement in meters.

Now we differentiate this eq. of displacement to get the equation of velocity:

$v=\frac{d}{dt}(s) \\v=6t^2-6t-63$

According to given the velocity is $99\ m.s^{-1}$ at some time:

$99=6t^2-6t-63$

$6t^2-6t-162=0$

$t=5.72\ s$ & is the only time for (t>=0) instances when the particle will have a velocity of $99\ m.s^{-1}$ but in the opposite direction.

8 0

4 years ago

The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 {\rm rpm} .

damaskus [11]

Answer:

5833.33

Explanation:

$\alpha$ = Angular acceleration

$\theta$ = Number of revolutions

$\omega_i$ = Initial angular speed = 0

t = Time taken = 2 s

Final angular speed

$\omega_f=\dfrac{350000}{60}=5833.33\ rps$

From the equation of rotational motion we have

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{5833.33-0}{2}\\\Rightarrow \alpha=2916.665\ rev/s^2$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2916.665\times 2^2\\\Rightarrow \theta=5833.33\ rev$

The number of revolutions is 5833.33

6 0

3 years ago