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daser333 [38]
3 years ago
6

A gasoline engine receives 200 J of energy from combustion and loses 150 J as heat to the exhaust. What is its efficiency? 75% 2

5% 33% 125%
Physics
2 answers:
choli [55]3 years ago
8 0
50/200×100%=25% is answer the formula is usefull energy output divided by total energy provided into 100%
rjkz [21]3 years ago
7 0
25%.

Efficiency, in this case, means the work done...
Heat is a by-product of combustion and is lost energy. What remains the work done by the engine.

Our of 200 J, only 50 J are left out of 200 J.

So, 50 J remaining divided by 200 total I

50/200 = 1/4 = 25%

If you have any questions then please comment.
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Answer:

Part a)

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Part b)

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Explanation:

Part a)

Level of sound = 75 dB

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L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

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Part b)

Intensity of sound wave is given as

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A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

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