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daser333 [38]
3 years ago
6

A gasoline engine receives 200 J of energy from combustion and loses 150 J as heat to the exhaust. What is its efficiency? 75% 2

5% 33% 125%
Physics
2 answers:
choli [55]3 years ago
8 0
50/200×100%=25% is answer the formula is usefull energy output divided by total energy provided into 100%
rjkz [21]3 years ago
7 0
25%.

Efficiency, in this case, means the work done...
Heat is a by-product of combustion and is lost energy. What remains the work done by the engine.

Our of 200 J, only 50 J are left out of 200 J.

So, 50 J remaining divided by 200 total I

50/200 = 1/4 = 25%

If you have any questions then please comment.
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Explanation & answer:

Given:

Fuel consumption, C = 22 L/h

Specific gravity = 0.8

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heating value, H = 44,000 kJ/kg

Solution:

Calculate energy intake

E = C*P*H

= (22 L/h) / (3600 s/h) * (1000 mL/L) * (0.8 g/mL) * (44000 kJ/kg)

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= 215111.1 j/s

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Efficiency

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Answer:

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Explanation:

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4 0
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