3 years ago

19. Find the recoil velocity of a 65 kg ice hockey goalie who

Physics

1 answer:

Alexxx [7]3 years ago

4 0

Answer:

c. 0.12 m/s

Explanation:

by using momentum formula $v_2=\frac{m_1\times v_1}{m_1+m_2}$

we get

$v_2=\frac{0.15\times 50}{0.15+65}=0.12$

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Explanation:

We can solve this problem by using Charle's law, which states that for a gas kept at constant pressure, the volume of the gas (V) is proportional to its absolute temperature (T):

$\frac{V}{T}=const.$

Which can be also re-written as

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where

$V_1, V_2$ are the initial and final volumes of the gas

$T_1, T_2$ are the initial and final temperature of the gas

For the gas in the balloon in this problem, we have:

$V_1 = 7.00\cdot 10^2 mL = 700 mL$ is the initial volume

$T_1=20.0^{\circ}C+273=293 K$ is the initial absolute temperature

$V_2$ is the final volume

$T_2 = 1.00\cdot 10^2 K = 100 K$ is the final temperature

Solving for $V_2$ ,

$V_2 = \frac{V_1 T_2}{T_1}=\frac{(700)(100)}{293}=238.9 mL$

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An ambulance driver traveling at 31.0 m/s (69.3 mph) honks his horn as he sees a motorist ahead on the highway traveling in the

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Answer:

fo = 378.52Hz

Explanation:

Using Doppler effect formula:

$f'=\frac{C-Vb}{C-Va}*fo$

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Va = 31m/s

Replacing these values and solving for fo:

fo = 378.52Hz

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He must run at 6m/s

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you have 28 psi in the tire

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