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3 years ago

Find the height of this triangle.

Mathematics

1 answer:

MissTica3 years ago

8 0

x^2 = 4^2 - 2^2

x^2 = 16 - 4

x^2 = 12

x = √12

x = 2√3

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3 ( x - 2 ) + 5 x = 18

Anna11 [10]

Answer:

3 is correct answer

Step-by-step explanation:

$3(x - 2) + 5x = 18 \\ 3x - 6 + 5x = 18 \\ 8x - 6 = 18 \\ 8x = 18 + 6 \\ 8x = 24 \\ x = \frac{24}{8} \\ x = 3$

hope it helped you:)

3 0

3 years ago

Read 2 more answers

The pH of a solution ranges from 0 to 14. An acid has a pH less than 7. Pure water is neutral and has a pH of 7. The pH of a sol

abruzzese [7]

We need to know some log properties

1. when the base is not stated, assume that it is base 10 or log₁₀
2. $log_aa^x=x$

-log(10^-1)= $log_{10}10^{-1}=-1$

answer is D. -1

3 0

3 years ago

Scott bought a 5lb bag of cookies at the bakery. He ate 2/5 of the bag and his sister ate 2/9 of the bag. What fraction of the b

satela [25.4K]

Answer: Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

Step-by-step explanation:

Given: Part of cookies eaten by Scott = $\dfrac25$

Part of cookies eaten by sister = $\dfrac{2}{9}$

Fraction they both eat = $\dfrac25+\dfrac29=\dfrac{9\times2+5\times2}{5\times9}$

$=\dfrac{18+10}{45}\\\\=\dfrac{28}{45}$

Fraction of the bag remain = $1-\dfrac{28}{45}=\dfrac{45-28}{45}=\dfrac{17}{45}$

[Taking fraction of whole bag =1]

Hence, Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

4 0

3 years ago

44/35 as a mixed number

joja [24]

44/35 = 1 9/35

So, your answer is 1 9/35

4 0

3 years ago

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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$

7 0

3 years ago