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3 years ago

What materials electricians should avoid wearing.

Physics

2 answers:

Nady [450]3 years ago

7 0

It believe its fire repellant clothing.

Rainbow [258]3 years ago

4 0

Arc flash PPE

Coveralls

Fire replant clothing

vest

safety gloves and footwear

You might be interested in

What is the Unit used to measure voltage

muminat

The derived unit for voltage is named volt.

3 0

3 years ago

A galaxy spectrum has a redshift of 70,000 km per second. If the Hubble constant is 70 km per second per Mpc (megaparsec), how f

gogolik [260]

Using the Hubble law v = H₀d where v = recessional speed = 70,000 km per second H₀ = hubble constant = 70 km/s/Mpc and d = distance of galaxy.

Making d subject of the formula, we have

d = v/H₀

Substituting the values of the variables into the equation, we have

d = v/H₀

d = 70000 km/s/70 km/s/Mpc

d = 1000 Mpc

So, the galaxy is 1000 Mpc away from us.

Learn more about hubble law here:

brainly.com/question/18484687

8 0

3 years ago

A change in the size or shape of a substance is a ___________ change. physical, chemical, or nuclear?

Pachacha [2.7K]

The answer would be physical.

6 0

3 years ago

Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1

Nonamiya [84]

Answer:

$a_x=6\ \text{m/s}^2$ and $a_y=0\ \text{m/s}^2$

Magnitude of accleration is $6\ \text{m/s}^2$ and the direction is $0^{\circ}$

Explanation:

$t_1=2\ \text{s}$

$v_x=1\ \text{m/s}$

$v_y=3\ \text{m/s}$

$t_2=2.5\ \text{s}$

$v_x=4\ \text{m/s}$

$v_y=3\ \text{m/s}$

Average acceleration in the different axes

$a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2$

$a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2$

The components of the acceleration is $a_x=6\ \text{m/s}^2$ and $a_y=0\ \text{m/s}^2$

The magnitude of acceleration

$a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2$

Direction

$\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}$

The magnitude of accleration is $6\ \text{m/s}^2$ and the direction is $0^{\circ}$ .

7 0

2 years ago

The car has a maximum acceleration of 4m/s2 . The car’s mass is 1,250 Kg what is the car max speed?

marusya05 [52]

The net force acting on the car is
3 × 10^3
Newtons.
Force is defined as the product of the mass of the body and its aaceleration,
⇒ F = ma

Substituting the above given values we get,
F =(1500kg) (2.0 m/s^2) = 3000N = 3 × 10^3N .

3 0

2 years ago