The net force on the rocket is 846400 N.
Answer:
Explanation:
It is known that weight is the influence of gravitational force acting on any mass of the object. So in the present case, the weighing force given is equal to the gravitational force acting on the rocket. Thus, the gravitational force will be acting towards downward direction. But an upward force is required by the rocket for thrusting purpose and that force is given as upward force. So the net force acting on the rocket is the vector addition of all the forces acting on the rocket. As in this case, only upward and downward force is acting on the rocket. The vector addition will be equal to subtraction of downward acting gravitational force from upward force or force provided by engine.
Net force = Engine force - Gravitational force = 890000-43600=846400 N
So the net force acting on the rocket is 846400 N.
<span>Answer:
F = ma
Fx = max
WHERE:
Fx = forces in the x direction
m = mass
ax = acceleration in the x direction
If we look at the figure, there are only two forces in the x direction. The first force is the x component force 4.0 N acting to the right, denoted as +4.0 N. The second force is the 2.0 N force acting to the left, denoted as -2.0 N.
Fx = max
4.0 N - 2.0 N = (7.8 kg)*ax
2.0 N = (7.8 kg)*ax
ax = 0.25641 m/s^2
Because the question is asking you to write it to two significant figures,
==>ax = 0.26 m/s^2</span>
The density of the body and the height or the depth of the body since the formula of liquid pressure is density x height gravity
Given:
F = 4.719 N, the applied force
a = 33 m/s², the acceleration
Let m = the mass.
By definition,
F = m*a
Therefore,
m = F/a
= (4.719 N)/(33 m/s²)
= 0.143 kg
Answer: 0.143 kg