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2 years ago

How many atoms are present in the following compound? C21H22N2O2

Chemistry

1 answer:

alisha [4.7K]2 years ago

6 0

Acetic Acid has two C atoms, four H atoms, and two O atoms, so the molecular formula is C2H4O2.

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Calculation: If a compound is 14.40% hydrogen by mass and 85.60% carbon by mass, what is the empirical formula?

IgorLugansk [536]

Answer:

CH2

Explanation:

We are given that a compound is 14.40% hydrogen and 85.60% carbon.

Let the mass of the substance be 100g.

Mass of the hydrogen: 14.40% of 100 = 14.40 g

Mass of the carbon: 85.60% of 100 = 85.60 g

Now, let's find the moles of hydrogen:

$14.40 g*\frac{1 mole}{1gH} = 14.40 mole$

Moles of carbon:

$85.60g*\frac{1 mol}{12gC} = 7.13mol$

Let's put these in a ratio and simplify:

7.13 mole C: 14.40 mole H

1 mole C: 2 mole H

Therefore, the empirical formula of this compound is CH2.

Hope this helps!! If you have any questions about my work, please let me know in the comments!

3 0

1 year ago

How many atoms are in 5.00g of carbon

melisa1 [442]

Answer:

2.51 x 1023 atoms C

Explanation:

MW C = 12.011

5g x (1mol/12.011g) =0.416 mol

0.416 mol x (6.022x10^23) = 2.51 x 1023 atoms C

5 0

3 years ago

C is the element symbol for which element?<br>a. Carbon<br>b. Cadmium<br>c. Celenium<br>d. Chlorine

il63 [147K]

Answer:

A) Carbon

Explanation:

the others are wrong its A

6 0

2 years ago

Read 2 more answers

Anil accidentally swallows a substance that activates the complement cascade in the absence of bound antibodies. this substance

ale4655 [162]

Answer:

This substance would cause cause an extensive cellular damage to Anil.

5 0

1 year ago

Consider an electron with charge âˆ’eâˆ’e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with cha

PtichkaEL [24]

Answer:

Explanation:

The net force on electron is electrostatic force between electron and proton in the nucleus .

Fc = $\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}$

This provides the centripetal force for the circular path of electron around the nucleus .

Centripetal force required = $\frac{m\times v^2}{r}$

$\frac{m\times v^2}{r}=\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}$

$v^2=\frac{e^2}{4\pi \epsilon m r}$

$v=(\frac{e^2}{4\pi \epsilon m r})^{\frac{1}{2} }$

5 0

2 years ago