Molar mass ( CuSO₄) = 159.609 g/mol
159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules
mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³
mass = 5.36 x 10²⁴ / 6.02 x 10²³
mass = 8.90 g
hope this helps!
The equation that shows the decomposition of silver carbonate is as follows:
<span>2Ag2CO3 .........> 4Ag + 2CO2 + O<span>2
From the periodic table:
mass of silver = 107.8682 grams
mass of carbon = 12 grams
mass of oxygen = 16 grams
molar mass of Ag2CO3 = 2(107.8682) + 12 + 3(16) = 275.7364 grams
From the balanced equation above:
2(275.7362) = 551.4728 grams of Ag2CO3 produces 4(107.8682) = 431.4728 grams of Ag
Therefore, to know the mass of Ag produced from 2.76 grams of Ag2CO3, we will simply use cross multiplication as follows:
mass of Ag produced = (2.76*431.4728) / (551.4728) = 2.16 grams
Based on the above calculations, the law of conservation of mass is applied.</span></span>
Answer:
54
Explanation:
Given symbol of the element:
I⁻
Number of electrons found in an ion with the symbol:
This is a iodine ion:
For an atom of iodine:
Electrons = 53
Protons = 53
Neutrons = 74
An ion of iodine is one that has lost or gained electrons.
For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.
So, number of electrons = 53 + 1 = 54
The number of electrons in this ion is 54
Answer:
328.1 K.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT</em>.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in.
- If n is constant, and have two different values of (P, V and T):
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).
P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.
<em>T₂ = P₂V₂T₁/P₁V₁ = </em>(0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) <em>= 328.1 K.</em>
<em></em>
<h3>Answer:</h3>
We will neither give the Hypertonic Solution nor the Isotonic Solution but the patient will be given an Hypotonic Solution.
<h3>Explanation:</h3>
As the patient is taken for heat stroke and has resulted in dehydration so it means that the water content in the cells of the patient has been decreased and the solute content is being increased. Hence, this case is known as <em>Hypertonicity</em>. So, in order to make the concentration of water and solute balance (<em>Isotonicity</em>) on both sides (inside and outside the cells) we should administer an <em>Hypotonic solution</em> into the patient body. Therefore, the higher concentration of solutes in cells will drag the water content from hypotonic solution and gradually the process will attain an isotonic environment.