Answer:
Ka = 4.9 x 10ˉ⁴
Explanation:
HOAc ⇄ H⁺ + OAcˉ
Ka = [H⁺][OAcˉ]/[HOAc]
Given pH = 2.58 => [H⁺] = [OAcˉ] = 10ˉ²∙⁵⁸ = 2.63 x 10ˉ³M
Ka = (2.63 x 10ˉ³)²/(0.0142) = 4.9 x 10ˉ⁴
Freezing the substance and condensing it will not increase the entropy of a substance. In fact, dissolving the substance into water is the only way to increase the entropy of a certain substance. The entropy increases because it diversify with each other.
<span>We know the relation between heat and temperature follows the formula:
Q = Ce * m * (Tf-Ti) , where Q is heat transfer, Ce is specific heat, m is mass, Tf is final temperature and Ti is initial temperature.
Note that heat value is given in kj so we need to change to joules, then as heat is absorbed the final temperature will increase.
4,689 = 0.385 * 34.2 * (Tf-24)
Tf = 4,689 / (0.385 * 34.2) + 24 =380.12ÂşC</span>