Explain the general properties of group 1 elements in relation to their electronic configuration
2 answers:
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x = 0.83 L
Answer: d=2000 g/L
Explanation:
Density is mass/volume. The units are g/L. Since we are given mass and volume, we can divide them to find density. First, we need to convert kg to g.
Now that we have grams, we can divide to get density.
d=2000g/L
The question is incomplete, here is the complete question:
A 50 mL solution is initially 1.52% MgCl₂ by mass and has a density of 1.05 g/mL
What is the freezing point of the solution after you add an additional 1.37 g MgCl₂? (Use i = 2.5 for MgCl₂).
<u>Answer:</u> The freezing point of solution is -0.808°C
<u>Explanation:</u>
To calculate the mass of solution, we use the equation:
Density of solution = 1.05 g/mL
Volume of solution = 50 mL
Putting values in above equation, we get:
We are given:
Percentage of magnesium chloride in the solution = 1.52 %
Mass of magnesium chloride in the solution = 1.52 % of 52.5 g =
The equation used to calculate depression in freezing point follows:
To calculate the depression in freezing point, we use the equation:
Or,
where,
Freezing point of pure solution (water) = 0°C
i = Vant hoff factor = 2.5
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (magnesium chloride) = [0.798 + 1.34] g = 2.138 g
= Molar mass of solute (magnesium chloride) = 95.2 g/mol
= Mass of solvent (water) = [52.5 - 0.798] g = 51.702 g
Putting values in above equation, we get:
Hence, the freezing point of solution is -0.808°C