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Vikki [24]
3 years ago
10

Explain the general properties of group 1 elements in relation to their electronic configuration​

Chemistry
2 answers:
kodGreya [7K]3 years ago
6 0

Answer:

The elements in Group 1 (lithium, sodium, potassium, rubidium, cesium, and francium) are called the alkali metals. All of the alkali metals have a single s electron in their outermost principal energy. ... For example, the electron configuration of lithium (Li), the alkali metal of Period 2, is 1s22s1.

xeze [42]3 years ago
5 0

Answer:

they have a mono positive charge of +1

Explanation:

this is due to having one electron in their outermost ns orbital

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V₀(HNO₂) = V₀(NaNO₂)  = 1 dm³ = 1 L.
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n₀(HNO₂)= 1,2 mol/dm³ · 1 dm³ = 1,2 mol.
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V(NaOH) = 400 mL · 0,001 dm³/mL = 0,4 dm³.
n₀(NaOH) = c₀(NaOH) · V₀(NaOH).
n₀(NaOH) = 0,5 mol/dm³ · 0,4 dm³ = 0,2 mol.
n(HNO₂) = 1,2 mol - 0,2 mol = 1 mol.
n(NaNO₂) = 0,8 mol + 0,2 mol = 1 mol.
c(HNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
c(NaNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
pH = pKa + log (c(HNO₂) / c(NaNO₂)).
pH = 3,4 + log (0,714 mol/dm³ / 0,714 mol/dm³) = 3,4.
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