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Vikki [24]
3 years ago
10

Explain the general properties of group 1 elements in relation to their electronic configuration​

Chemistry
2 answers:
kodGreya [7K]3 years ago
6 0

Answer:

The elements in Group 1 (lithium, sodium, potassium, rubidium, cesium, and francium) are called the alkali metals. All of the alkali metals have a single s electron in their outermost principal energy. ... For example, the electron configuration of lithium (Li), the alkali metal of Period 2, is 1s22s1.

xeze [42]3 years ago
5 0

Answer:

they have a mono positive charge of +1

Explanation:

this is due to having one electron in their outermost ns orbital

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During the process of condensation, water vapor:____________.
monitta

Answer: (2) releases 2260 J/g of heat energy

Explanation:

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Latent heat of condensation is energy released when 1 mole of  vapor condenses to form liquid droplets.

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7 0
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Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
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Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

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I know about this, I think this is the answer. Try it out!!

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