All categories

3 years ago

Explain the general properties of group 1 elements in relation to their electronic configuration

Chemistry

2 answers:

kodGreya [7K]3 years ago

6 0

Answer:

The elements in Group 1 (lithium, sodium, potassium, rubidium, cesium, and francium) are called the alkali metals. All of the alkali metals have a single s electron in their outermost principal energy. ... For example, the electron configuration of lithium (Li), the alkali metal of Period 2, is 1s22s1.

xeze [42]3 years ago

5 0

Answer:

they have a mono positive charge of +1

Explanation:

this is due to having one electron in their outermost ns orbital

You might be interested in

Which sub-layer thins out into space, where there is no air

KengaRu [80]

The "exosphere" is the most distant and tenuous "layer" of our atmosphere.

3 0

3 years ago

Read 2 more answers

What is the pH of a 0.028M solution (pH=-log(M)) A) 3.56 B)2.88 C)1.55 D)1

Andrew [12]

Answer:

Explanation:

-log(0.028)=1.55

8 0

4 years ago

Read 2 more answers

As the toy car rolls away, it slows down. Why?

Morgarella [4.7K]

You need to show a picture or else we can’t help you

8 0

3 years ago

Read 2 more answers

At the end of which era did the dinosaurs became extinct?

evablogger [386]

Answer:

Cretaceous Period

Explanation:

Dinosaurs went extinct about 65 million years ago (at the end of the Cretaceous Period), after living on Earth for about 165 million years.

8 0

3 years ago

Read 2 more answers

a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter

ladessa [460]

Answer:

The concentration of chloride ion is $2.82\times10^{-3}\;mol/L$

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the $Cl^-$ content 100 ppm suggests the presence of 100 mg of $Cl^-$ in 1 L of solution.

The molar mass of $Cl^-$ is equal to the molar mass of Cl atom as the mass of the excess electron in $Cl^-$ is negligible as compared to the mass of Cl atom.

So, the molar mass of $Cl^-$ is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of $Cl^-$ present in 100 mg (0.100 g) of $Cl^-$ is calculated as shown below:

$N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol$

So, there is $2.82\times10^{-3}\;mol$ of $Cl^-$ present in 1 L of solution.

5 0

4 years ago

Explain the general properties of group 1 elements in relation to their electronic configuration​

Explain the general properties of group 1 elements in relation to their electronic configuration