PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST

Chemistry

2 answers:

dusya [7]3 years ago

8 0

1 to 4) it’s weird yeah doesn’t like you choose your subject

Ivahew [28]3 years ago

5 0

Answer:

up to down(1 to 6)

Explanation:

speed:

1,3,4

Velocity:

everything except 1,3,4

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1. What is the mass of 22.4 L of H2 at STP?

Fed [463]

1.
n = m/2.016 g/mol = V/22.4 l
V = 22.4 l
Hence,
m = 2.016 g ≈ 2.02 g
B.) 2.02 g

2.
Balancing the equation, we get,
Mg + 2HCl → MgCl2 + H2
PV = nRT
V = nRT/P
V = 1.5 mol × 8.314 atm/(mol.K) × 298 K/(0.96 atm)
V = 3871.206
V ≈ 38.2 l

6 0

3 years ago

Read 2 more answers

Xenon (xe) of mass 5.08 g reacts with fluorine to form 9.49 g of a xenon fluoride compound. what is the empirical formula of thi

jenyasd209 [6]

We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.

mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g

Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F

The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>

8 0

3 years ago

In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area

storchak [24]

First we must write a balanced chemical equation for this reaction

$Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)$

The mole ratio for the reaction between $HNO_3$ and $Na_2CO_3$ is 1:2. This means 1 moles of $Na_2CO_3$ will neutralize 2 moles $HNO_3$ . Now we find the moles of each reactant based on the mass and molar mass.