1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksian1 [2.3K]
2 years ago
15

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST

Chemistry
2 answers:
dusya [7]2 years ago
8 0
1 to 4) it’s weird yeah doesn’t like you choose your subject
Ivahew [28]2 years ago
5 0

Answer:

up to down(1 to 6)

Explanation:

speed:

1,3,4

Velocity:

everything except 1,3,4

You might be interested in
How can you remember an individual element's ionic charge?
docker41 [41]

Answer:

write it down

Explanation:

6 0
3 years ago
Read 2 more answers
What is the best definition for the underlined word based on the following sentence?
svet-max [94.6K]
What is  the underlined word


5 0
3 years ago
Read 2 more answers
C. 49.8 grams of ki is dissolved in enough water to make 1.00 l of solution. what is the molarity?
taurus [48]

Hey There!:


Molar Mass KI => 166.003 g/mol


* number of moles:


n = mass of solute / molar mass


n = 49.8 / 166.003


n = 0.3 moles KI


Therefore:


M = n / V


M = 0.3 / 1.00


M = 0.3 mol/L


hope this helps!

7 0
3 years ago
Read 2 more answers
How many formula units are there in 450 g of Na2S04?
Mashutka [201]

Formula units in 450 g of Na_{2} So_{4} is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$\frac{450 g}{142.04 g/mol} =  3.2 moles

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.

So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.

4 0
3 years ago
A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the
horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 Cm^{3}

First, find the Density of given substance.

Formula used :    

Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}

Now,put all the values in this formula, we get

Density=\frac{46.9 g}{3.5 Cm^{3} } = 13.4 g/Cm^{3}

So, we conclude that the density of given substance (13.4 g/Cm^{3}) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/Cm^{3} respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

3 0
3 years ago
Read 2 more answers
Other questions:
  • You have a strong solution of lemonade that you need to dilute before serving. During the dilution which of the following will c
    8·1 answer
  • Compounds formed by the combination of metals and oxygen
    13·1 answer
  • HELP ASAPPP!!!!’........
    10·1 answer
  • What are valence electrons?
    12·1 answer
  • Vibrations within the ________ are sent to the brain, where the sound is interpreted.
    12·1 answer
  • In the film, Lavoisier said that the mass gained by the pipe plus the mass of the collected gas "exactly" equaled the lost mass
    8·1 answer
  • In the reaction __H2 + O2 → 2H2O, what coefficient should be placed in front of H2 to balance the reaction?
    5·2 answers
  • Is tar used to manufacture coal tar and coke
    8·1 answer
  • Is salt a iconically bounded compound?
    11·2 answers
  • A 435.0 g sample of CaCO3 that is 95% pure gives 225L of CO2 when reacted with excess of hydrochloric acid. What is the density
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!