1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FinnZ [79.3K]
3 years ago
9

The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?

Chemistry
2 answers:
nexus9112 [7]3 years ago
8 0
In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4
Stels [109]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

According to ideal gas equation, the product of pressure and volume is equal to the product of universal gas constant and absolute temperature.

Mathematically,      PV = nRT       ........... (1)

where       P = pressure

                V = volume

               n = number of moles

              R = gas constant

              T = temperature

Also, number of moles = \frac{mass of atom}{molar mass of the atom}

Therefore, number of moles of oxygen atom will be as follows.

    Number of moles = \frac{mass of atom}{molar mass of the atom}

                                  = \frac{8}{32}

                                  = \frac{1}{4}

Thus, putting the value of n into equation (1) as follows.

                                PV = nRT

      or                      PV = \frac{1}{4}RT

You might be interested in
A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure
Leni [432]

Answer:  (27.81,\ 29.39)

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : \alpha: 1-0.95=0.05

Critical value: z_{\alpha/2}=1.96

Sample mean : \overline{x}=28.6

Standard deviation : \sigma=2.2

The formula to find the confidence interval is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}

i.e. 28.6\pm 0.787259889321

\approx28.6\pm 0.79=(28.6-0.79,28.6+0.79)=(27.81,\ 29.39)

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = (27.81,\ 29.39)

4 0
3 years ago
The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
Which of the following has the largest radius?<br><br><br> Answer:K
mixas84 [53]

Answer:

the answer is k? lol thanks

4 0
3 years ago
A light bulb has a resistance of 96.8 Ω. What current flows through the bulb when it is connected to a 120 V source of electrica
Finger [1]

Answer:

I = 1.23 A

Explanation:

Given that,

The resistance of the lightbulb, R = 96.8 Ω

Voltage, V = 120 V

We need to find the current flows through the lightbulb. Let the current be I. We can use the ohm's law to find it i.e.

V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{120}{96.8}\\\\I=1.23\ A

So, the current flows through the bulb is 1.23 A.

8 0
2 years ago
Question 6: what do i fill in the blank space? what are the units?
Arte-miy333 [17]

Answer:

I don't know chemistry

Explanation:

because this is the hardest subject in the world nobody can solve it so do yourself ok Beta

3 0
2 years ago
Read 2 more answers
Other questions:
  • The combustion of glucose (c6h12o6) with oxygen gas produces carbon dioxide and water. this process releases 2803 kj per mole of
    11·1 answer
  • Is the capacity to do work or to produce heat.
    7·1 answer
  • How many moles of electrons are transferred in the folllowing balanced chemical equation 4fe + 3o2?
    14·1 answer
  • Which of the following is a unit of mass?
    5·1 answer
  • A gas has a volume of 46.0 L when the temperature is 400. K. When the temperature changes to 500. K, what is the new volume, if
    6·1 answer
  • If you have exactly 2.00 moles each, of two different substances, then which of the following must be true about the two samples
    9·1 answer
  • Will a cold snowball give off cold air?
    6·1 answer
  • The mitochondria is ____where
    8·1 answer
  • Define respiration in plants:
    14·2 answers
  • Which species is the conjugate base of H2SO3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!