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FinnZ [79.3K]
4 years ago
9

The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?

Chemistry
2 answers:
nexus9112 [7]4 years ago
8 0
In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4
Stels [109]4 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

According to ideal gas equation, the product of pressure and volume is equal to the product of universal gas constant and absolute temperature.

Mathematically,      PV = nRT       ........... (1)

where       P = pressure

                V = volume

               n = number of moles

              R = gas constant

              T = temperature

Also, number of moles = \frac{mass of atom}{molar mass of the atom}

Therefore, number of moles of oxygen atom will be as follows.

    Number of moles = \frac{mass of atom}{molar mass of the atom}

                                  = \frac{8}{32}

                                  = \frac{1}{4}

Thus, putting the value of n into equation (1) as follows.

                                PV = nRT

      or                      PV = \frac{1}{4}RT

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sukhopar [10]

Answer:

  • <u><em>Yes, 200 ml of fluid can be transferred to a 1-quart container.</em></u>

Explanation:

You must compare the two volumes, 200 ml and 1 quart. If 200 ml is less than or equal to 1 quart, then 200 ml of fluid can be transferred to a 1-quart container, else it is not possible.

To compare, the two volumes must be on the same system of units.

Quarts is a measure of volume equivalent to 1/4 of gallon.

One gallon is approximately 3.785 liters.

3.785 liter = 3.785 liter × 1,000 ml/liter

Then, to convert 1 quart to ml use the unit cancellation method:

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Thus, you get that a 1-quart container has volume of 946.25 ml, which allows that 200ml of fluid be transferred to it.

7 0
4 years ago
How many moles of Aluminum are produced when34.2 g of alumina are broken down through the process of electrolysis
Elan Coil [88]

Answer:

0.670 mol

Explanation:

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2 Al₂O₃ ⇒ 4 Al + 3 O₂

Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃

The molar mass of Al₂O₃ is 101.96 g/mol.

34.2 g × 1 mol/101.96 g = 0.335 mol

Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃

The molar ratio of Al₂O₃ to Al is 2:4.

0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al

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3 years ago
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3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
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