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FinnZ [79.3K]
3 years ago
9

The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?

Chemistry
2 answers:
nexus9112 [7]3 years ago
8 0
In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4
Stels [109]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

According to ideal gas equation, the product of pressure and volume is equal to the product of universal gas constant and absolute temperature.

Mathematically,      PV = nRT       ........... (1)

where       P = pressure

                V = volume

               n = number of moles

              R = gas constant

              T = temperature

Also, number of moles = \frac{mass of atom}{molar mass of the atom}

Therefore, number of moles of oxygen atom will be as follows.

    Number of moles = \frac{mass of atom}{molar mass of the atom}

                                  = \frac{8}{32}

                                  = \frac{1}{4}

Thus, putting the value of n into equation (1) as follows.

                                PV = nRT

      or                      PV = \frac{1}{4}RT

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Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

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x_i+x_2=1

x_2 = 1- x_i

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x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

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\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

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As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

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