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SCORPION-xisa [38]

3 years ago

8

A giant solar flare struck Earth in 1859, but it didn't seem to cause much damage. Why do people worry about one that large hitt

ing now? HELPPPPPP

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

electronics getting fried do to the electromagnetic surge. (the solar flare can act like an emp)

Explanation:

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A 1.5m wire carries a 3 A current when a potential difference of 74 V is applied. What is the resistance of the wire?

Allisa [31]

Answer:

24.7 ohms

Explanation:

Given in the question,

electric current = 3 A

potential difference = 74 V

Using ohm's law

<h3>V = IR</h3>

R = V/I

<em>here,</em>

<em>R = resistance of wire</em>

<em>V = potential difference</em>

<em>I = electric current</em>

<em />

plug value in the formula

R = 74/3

R = 24.7 ohms

Therefore, the resistance of the wire is, 24.7 ohms

4 0

3 years ago

Karyn is a zookeeper who takes care of baboons. Each day, Karyn writes down how the baboons eat, play, sleep, and wash. She revi

hodyreva [135]

The statement which explains why Karyn's approach is an investigation instead because she is not attempting to change outcomes.

<h3>What is Investigation?</h3>

This is defined as the systematic study of a subject topic and involves various forms of observation.

It however doesn't involve measuring variable as the outcomes aren't changed but only recorded.

Read more about Investigation here brainly.com/question/3897229

#SPJ1

5 0

2 years ago

HELP ME 100 POINTS PLEASE BRAINIEST IF CORRECT!!!!!!!

WITCHER [35]

Answer:

a

Explanation:

the color reflected is the color you see

7 0

3 years ago

Read 2 more answers

A river 500 ft wide flows with a speed of 8 ft/s with respect to the earth. A woman swims with a speed of 4 ft/s with respect to

White raven [17]

Answer:

1) $\Delta s=1000\ ft$

2) $\Delta s'=998.11\ ft.s^{-1}$

3) $t\approx125\ s$

$t'\approx463.733\ s$

Explanation:

Given:

width of river, $w=500\ ft$

speed of stream with respect to the ground, $v_s=8\ ft.s^{-1}$

speed of the swimmer with respect to water, $v=4\ ft.s^{-1}$

<u>Now the resultant of the two velocities perpendicular to each other:</u>

$v_r=\sqrt{v^2+v_s^2}$

$v_r=\sqrt{4^2+8^2}$

$v_r=8.9442\ ft.s^{-1}$

<u>Now the angle of the resultant velocity form the vertical:</u>

$\tan\beta=\frac{v_s}{v}$

$\tan\beta=\frac{8}{4}$

$\beta=63.43^{\circ}$

Now the distance swam by the swimmer in this direction be d.

so,

$d.\cos\beta=w$

$d\times \cos\ 63.43=500$

$d=1118.034\ ft$

Now the distance swept downward:

$\Delta s=\sqrt{d^2-w^2}$

$\Delta s=\sqrt{1118.034^2-500^2}$

$\Delta s=1000\ ft$

2)

On swimming 37° upstream:

<u>The velocity component of stream cancelled by the swimmer:</u>

$v'=v.\cos37$

$v'=4\times \cos37$

$v'=3.1945\ ft.s^{-1}$

<u>Now the net effective speed of stream sweeping the swimmer:</u>

$v_n=v_s-v'$

$v_n=8-3.1945$

$v_n=4.8055\ ft.s^{-1}$

<u>The component of swimmer's velocity heading directly towards the opposite bank:</u>

$v'_r=v.\sin37$

$v'_r=4\sin37$

$v'_r=2.4073\ ft.s^{-1}$

<u>Now the angle of the resultant velocity of the swimmer from the normal to the stream</u>:

$\tan\phi=\frac{v_n}{v'_r}$

$\tan\phi=\frac{4.8055}{2.4073}$

$\phi=63.39^{\circ}$

Now let the distance swam in this direction be d'.

$d'\times \cos\phi=w$

$d'=\frac{500}{\cos63.39}$

$d'=1116.344\ ft$

<u>Now the distance swept downstream:</u>

$\Delta s'=\sqrt{d'^2-w^2}$

$\Delta s'=\sqrt{1116.344^2-500^2}$

$\Delta s'=998.11\ ft.s^{-1}$

3)

Time taken in crossing the rive in case 1:

$t=\frac{d}{v_r}$

$t=\frac{1118.034}{8.9442}$

$t\approx125\ s$

Time taken in crossing the rive in case 2:

$t'=\frac{d'}{v'_r}$

$t'=\frac{1116.344}{2.4073}$

$t'\approx463.733\ s$

7 0

4 years ago

Why is si unit called coherent system

Sladkaya [172]

Answer:

The SI system is also called coherent system of units because of the following reasons: ... 1 Newton (SI unit of Force) = 1 Kg (SI unit of mass) x 1 m (SI unit of distance) / s2 (SI unit of time) , therefore 1 Newton is a coherent unit of Force.

HOPE ITS HELP

<h2><em>#</em><em>B</em><em>R</em><em>A</em><em>I</em><em>N</em><em>L</em><em>E</em><em>S</em><em>T</em></h2>

6 0

3 years ago