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scoundrel [369]
3 years ago
10

Which best describes a similarity between power plants that use water as an energy source and those that use wind as an energy s

ource?
A.Both use heat from within Earth to produce electricity.
B.Both use kinetic energy to produce electricity.
C.Both use resources that are not abundant.
D.Both use resources that produce a lot of air pollution.
Physics
2 answers:
stiks02 [169]3 years ago
6 0

The correct answer to the question is : B) Both use kinetic energy to produce electricity.

EXPLANATION:

Hydroelectricity is produced when the kinetic energy of the falling water rotates the turbine. The generator associated with the turbine is rotated, and electric energy is produced due to electric magnetic induction.

In case of power plants in which wind is used as energy source, the same process happens. The kinetic energy of wind rotates the propellers of wind turbine which in turn produces electric energy.

Hence, the correct similarity between them is statement B.

disa [49]3 years ago
3 0
The hydropower plant and wind turbines both uses kinetic energy to produce mechanical power and convert the mechanical energy using a generator to an electrical energy. They both have the process to produce energy but they differ in the source the hydropower plant uses water to whit the wind turbines power plant uses wind. Therefore the answer is letter B. 
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Is it possible to calculate the displacement based on an elapsed time from a position time graph?
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3 years ago
A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei
iragen [17]
<h3><u>Answer;</u></h3>

= 73 N

<h3><u>Explanation</u>;</h3>

Using the formula

2 T cos(30°) = w

Where; T is the tension on each string, while w is the weight of the box given by mg

Therefore;

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7 0
3 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
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Why is the linear coefficient of thermal expansion important for a restorative material?
iren2701 [21]

Additionally, the coefficient of thermal expansion of the restorative material should be comparable to the coefficient of thermal expansion of the tooth structure, since a significant difference between the two could result in thermal-induced stress at the cavity wall and subsequent marginal failure.

This study's objective was to assess how thermal stress affected the marginal integrity of restorative materials with various adhesive and thermal characteristics. As an alternative to clinical trials, which are expensive and time-consuming, evaluation of restorative materials under laboratory simulations of clinical function is frequently carried out. Thermal cycling regimens, which are in vitro techniques that subject the restoration and the tooth to extremely high temperatures, are frequently used in laboratory simulations to replicate thermal stresses that naturally occur in vivo.

Learn more about Thermal Stress here-

brainly.com/question/20309377

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