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3 years ago

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What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?

1 answer:

Alchen [17]3 years ago

8 0

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

When a simple pendulum swings back and forth, it has some energy associated with its motion.
The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
The potential energy of the simple pendulum is given by P.E = mgh
The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.

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An eagle flying at 35 m/s emits a cry whose frequency is 440 Hz. A blackbird is moving in the same direction as the eagle at 10

Akimi4 [234]

Answer:

a) $F=475.7Hz$

b) $F'=410.899Hz$

Explanation:

From the question we are told that:

Velocity of eagle $V_1=35m/s$

Frequency of eagle $F_1=440Hz$

Velocity of Black bird $V_2=10m/s$

Speed of sound $s=343m/s$

a)

Generally the equation for Frequency is mathematically given by

$F=f_0(\frac{v-v_2}{v-v_1})$

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$F=475.7Hz$

b)

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$F'=440(\frac{343+10}{343+35})$

$F'=410.899Hz$

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An object begins with a speed of 20 meters per second and slows down to a speed of 10 meters per second over a time of 5 seconds

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Answer:

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Answer:

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Explanation:

m = 1500 kg, h = 450 km, radius of earth, R = 6400 km

Let the acceleration due to gravity at this height is g'

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g' / g = {6400 / (6850)}^2

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