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Luba_88 [7]
3 years ago
6

WILL GIVE BRAINLIEST AND 50 POINTS!

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer: The function M if derived from the integral of the derivative of the function. This is valid by the fundamental theorem of calculus.

M(x)=43x32−7x+C

Step-by-step explanation: not 100 about this but it's what I got

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Find the arc length of a partial circle
marusya05 [52]

Answer:

12.5664 units (rounded off to four decimal values)

Step-by-step explanation:

Arc length = 2 × π × r × \frac{central-angle}{360}

For our partial circle;

The radius (r) = 8 units

The central angle = 90°

Arc length = 2 × π × 8 × \frac{90}{360} = 12.5663706144  units

Or 12.5664 units (rounded off to four decimal values)

5 0
3 years ago
Read 2 more answers
Convert the hexadecimal numeral to Hindu-Arabic <br> 4A9EDsixteen<br> 8
IceJOKER [234]

9514 1404 393

Answer:

  305,645 base 10

  1124755 base 8

Step-by-step explanation:

In expanded form, the number is ...

  4×16^4 +10×16^3 +9×16^2 +14×16^1 +13

  = (((4×16 +10)×16 +9)×16 +14)×16 +13 = ((74×16 +9)×16 +14)×16 +13

  = (1193×16 +14)×16 +13 = 19102×16 +13 = 305,645 base 10

_____

If you want to convert this to base 8, that is easily done by writing the binary equivalents of the hex digits, then regrouping them by 3s.

  4A9ED₁₆ = 0100 1010 1001 1110 1101₂ = 01 001 010 100 111 101 101₂

  = 1124755₈

5 0
3 years ago
Help meeeeeeeeeeeeee​
valina [46]

Answer:36!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
What is 1/3 plus 1/2 in fraction form
Citrus2011 [14]

Answer:

5/6

Step-by-step explanation:

Hope this helped!!!

7 0
2 years ago
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