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Cloud [144]
3 years ago
15

Compute the work (in joules) required to compress a spring 3 cm

Physics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

7×160=1120kj so,1120kj=1.12j.

Explanation:

Energy is equal to force times distance,so we add all the distance and we multiply them with the total force of the spring to get the answer. However, the answer is in kilojoules so we have to change it in to joules by dividing the answer into joules by 1000..

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Calculate the velocity of the objects motion represented in the following graph. Show all your work.
Leni [432]

as we know that velocity= displacement/change in time

hence velocity here is= 11-3/12-0

=8/12

=2/3

=0.667m/s

hopefully i am right

6 0
3 years ago
Which of the following DOES NOT demonstrate potential energy?
Elan Coil [88]

Answer:

D.

Explanation:

The man is moving and his energy isn't being stored up and stressed like the other options.

Sorry about the mix up I thought it said kinetic energy.

<em>Hope this helps.</em>

4 0
3 years ago
Read 2 more answers
How can you increase the magnitude of friction between two surfaces ? How can you decrease the magnitude of friction
Mice21 [21]
The frictional force between two surfaces is given by:
F_f = \mu F_p
where
\mu is the coefficienct of friction
F_p is the force with which one surface is pushed against the other one

Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction \mu (for instance, by making the surfaces more "rough"
2) by increasing F_p, the force  with which one surface is pushed against the other

Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force F_p
8 0
4 years ago
A long straight wire carries a 40.0 A current in the +x direction. At a particular instant, an electron moving at 1.0  107 m/s
ser-zykov [4K]

Answer:

F=-1.28\times 10^{-16}\ N

Explanation:

Given that,

Current flowing in the wire, I = 40 A (+x direction)

Speed of the electron, v=10^7\ m/s (+y direction)

Distance from the wire, r = 0.1 m

Let F is the electric force on the electron. It is given by :

F=qvB\ sin\theta

Here, \theta=90

F=qvB

Here, B=\dfrac{\mu_oI}{2\pi r}

F=qv\dfrac{\mu_oI}{2\pi r}

F=-1.6\times 10^{-19}\times 10^7\times \dfrac{4\pi\times 10^{-7}\times 40}{2\pi \times 0.1}

F=-1.28\times 10^{-16}\ N

So, the force on the electron at this instant is -1.28\times 10^{-16}\ N. Hence, this is the required solution.

5 0
4 years ago
Any object that is a magnet attracts is a magnetic ________.
Bumek [7]
<span>Any object that is a magnet attracts is a magnetic force.</span>
4 0
3 years ago
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