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Sloan [31]
3 years ago
11

You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides

120.0 volts, what is the current through this bulb?
Physics
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

Current, I = 0.029 A

Explanation:

It is given that,

Power of the nightlight plug, P = 3.5 watts

The voltage provided by the house circuit,V = 120 volts

We know that the power of an electrical appliance is given by :

Power = voltage × current

I=\dfrac{P}{V}

I=\dfrac{3.5\ W}{120\ V}

I = 0.029 A

Hence, the current through this bulb is 0.029 A. Hence, this is the required solution.        

nekit [7.7K]3 years ago
7 0
Base on the said question or problem that state and ask to calculate the current of the said light bulb and in my further calculation and further analysis, I would say that the current of the light bulb would be 0.0292. I hope you are satisfied with my answer and feel free to ask for more 
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Nuclear sizes are expressed in a unit named
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Answer is A) Fermi

Explanation:

Fermi is the expressive unit for nuclear sizes. Fermi = 10^-15 meter.

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Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
givi [52]

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An atom with the expected number of neutrons, protons, and electrons is called a(n)
ryzh [129]

Answer:

Stable atom

Explanation:

A stable atom is one that has a balanced nuclear inter-particle force reaction as such the binding energy of a stable atom is sufficient to permanently keep the nucleus as one unit. Examples of a stable atom are the atoms of  monoisotopic elements such as fluorine, sodium, iodine, gold, aluminium, and cobalt.

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6 0
3 years ago
An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
andrew-mc [135]

Answer:

The object will travel 675 m during that time.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.

In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

where:

  • x0 is the initial position.
  • v0 is the initial velocity.
  • a is the acceleration.
  • t is the time interval in which the motion is studied.

In this case:

  • x0= 0
  • v0= 0  because the object is initially stationary
  • a= 6 \frac{m}{s^{2} }
  • t= 15 s

Replacing:

x= 0 + 0*15 s + ½*6 \frac{m}{s^{2} }*(15s)²

Solving:

x=½*6 \frac{m}{s^{2} }*(15s)²

x=½*6 \frac{m}{s^{2} }*225 s²

x= 675 m

<u><em> The object will travel 675 m during that time.</em></u>

5 0
2 years ago
Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

t = time = 3 [s]

11 = 5 + a*3\\6=3*a\\a= 2[m/s^{2} ]

4 0
2 years ago
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