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Sloan [31]
3 years ago
11

You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides

120.0 volts, what is the current through this bulb?
Physics
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

Current, I = 0.029 A

Explanation:

It is given that,

Power of the nightlight plug, P = 3.5 watts

The voltage provided by the house circuit,V = 120 volts

We know that the power of an electrical appliance is given by :

Power = voltage × current

I=\dfrac{P}{V}

I=\dfrac{3.5\ W}{120\ V}

I = 0.029 A

Hence, the current through this bulb is 0.029 A. Hence, this is the required solution.        

nekit [7.7K]3 years ago
7 0
Base on the said question or problem that state and ask to calculate the current of the said light bulb and in my further calculation and further analysis, I would say that the current of the light bulb would be 0.0292. I hope you are satisfied with my answer and feel free to ask for more 
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Ymorist [56]

Answer: I would say the answer is B.

Explanation: It looks and sounds the most correct.

5 0
3 years ago
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. The acceleration
Debora [2.8K]

Answer:

The radius of the loop is  20.66 km

Explanation:

let the radius of the loop be r

mass of airplane is m

At the top, the pilot experiences two radial forces, which are

1) Gravitational force is  mg

2) Centrifugal forces mv²/r out of the center

When the pilot experiences no weight,

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r = v² / g

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3 0
3 years ago
Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = \frac{kQ_{1}Q_{2} }{r^{2} }

F= \frac{K(Q/2)(3Q/4)}{r^{2} }

how \frac{KQ^{2} }{r^{2} } = 0.42

Then

F = \frac{0.42*3}{8}

F = 0.1575 N

3 0
3 years ago
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Natali5045456 [20]

The correct answer is B two children pulling apart a wishbone

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6 0
3 years ago
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3 years ago
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