Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
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What's your favorite food or drink?
A. T= d/r
A good way to remember this is by making a pyramid with 3 parts and putting distance at the top and rate and time in the other two parts. This way you can visibly see the equation and use it if you need to find one for rate.
B. It's reasonable to write distance as a positive number because distance is always positive. You are not able to have a negative distance. Imagine someone standing on a side walk. Even if they are not moving, their distance is 0 which is positive. If they move backwards or forwards, their distance is still positive because it is more than that 0 and they are gaining something.
C. Just plug in the numbers into the formula.
T= d/r
T= 32.12 m /<span>8.8 m/min
T= 3.65 min
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N = -3
5n + n + 6 = -18 - 2n
6n + 6 = -18 - 2n
-6 to both sides
6n = -24 - 2n
+2n to both sides
8n = -24
divide 8 to both sides
n = -3
