All categories

2 years ago

Describe the process of how a bill becomes a law in at least 4-5 sentence

Physics

1 answer:

Lina20 [59]2 years ago

6 0

Answer:

Step 1: A Bill Is Born

Anyone may draft a bill; however, only members of Congress can introduce legislation, and, by doing so, become the sponsor(s). The president, a member of the cabinet or the head of a federal agency can also propose legislation, although a member of Congress must introduce it.

Step 2: Committee Action

As soon as a bill is introduced, it is referred to a committee. At this point the bill is examined carefully and its chances for passage are first determined. If the committee does not act on a bill, the bill is effectively "dead."

Step 3: Subcommittee Review

Often, bills are referred to a subcommittee for study and hearings. Hearings provide the opportunity to put on the record the views of the executive branch, experts, other public officials and supporters, and opponents of the legislation.

Step 4: Mark up

When the hearings are completed, the subcommittee may meet to "mark up" the bill; that is, make changes and amendments prior to recommending the bill to the full committee. If a subcommittee votes not to report legislation to the full committee, the bill dies. If the committee votes for the bill, it is sent to the floor.

Step 5: Committee Action to Report a Bill

After receiving a subcommittee's report on a bill the full committee votes on its recommendation to the House or Senate. This procedure is called "ordering a bill reported."

Step 6: Voting

After the debate and the approval of any amendments, the bill is passed or defeated by the members voting.

Step 7: Referral to Other Chamber

When the House or Senate passes a bill, it is referred to the other chamber, where it usually follows the same route through committee and floor action. This chamber may approve the bill as received, reject it, ignore it, or change it.

Step 8: Conference Committee Action

When the actions of the other chamber significantly alter the bill, a conference committee is formed to reconcile the differences between the House and Senate versions. If the conferees are unable to reach agreement, the legislation dies. If agreement is reached, a conference report is prepared describing the committee members' recommendations for changes. Both the House and Senate must approve the conference report

Step 9: Final Action

After both the House and Senate have approved a bill in identical form, it is sent to the president. If the president approves of the legislation, he signs it and it becomes law. Or, if the president takes no action for ten days, while Congress is in session, it automatically becomes law.If the president opposes the bill he can veto it; or if he takes no action after the Congress has adjourned its second session, it is a "pocket veto" and the legislation dies.

Step 10: Overriding a Veto

If the president vetoes a bill, Congress may attempt to "override the veto." If both the Senate and the House pass the bill by a two-thirds majority, the president's veto is overruled and the bill becomes a law.

Explanation:

good luck!

You might be interested in

Two particles with masses 2m and 9m are moving toward each other along the x axis with the same initial speeds vi. Particle 2m i

s2008m [1.1K]

Answer:

The final speed for the mass 2m is $v_{2y}=-1,51\ v_{i}$ and the final speed for the mass 9m is $v_{1f} =0,85\ v_{i}$ .

The angle at which the particle 9m is scattered is $\theta = -66,68^{o}$ with respect to the - y axis.

Explanation:

In an elastic collision the total linear momentum and the total kinetic energy is conserved.

<u>Conservation of linear momentum:</u>

Because the linear momentum is a vector quantity we consider the conservation of the components of momentum in the x and y axis.

The subindex 1 will refer to the particle 9m and the subindex 2 will refer to the particle 2m

$\vec{p}=m\vec{v}$

$p_{xi} =p_{xf}$

In the x axis before the collision we have

$p_{xi}=9m\ v_{i} - 2m\ v_{i}$

and after the collision we have that

$p_{xf} =9m\ v_{1x}$

In the y axis before the collision $p_{yi} =0$

after the collision we have that

$p_{yf} =9m\ v_{1y} - 2m\ v_{2y}$

$p_{xi} =p_{xf} \\7m\ v_{i} =9m\ v_{1x}\Rightarrow v_{1x} =\frac{7}{9}\ v_{i}$

then

$p_{yi} =p_{yf} \\0=9m\ v_{1y} -2m\ v_{2y} \\v_{1y}=\frac{2}{9} \ v_{2y}$

<u>Conservation of kinetic energy:</u>

$\frac{1}{2}\ 9m\ v_{i} ^{2} +\frac{1}{2}\ 2m\ v_{i} ^{2}=\frac{1}{2}\ 9m\ v_{1f} ^{2} +\frac{1}{2}\ 2m\ v_{2f} ^{2}$

$\frac{11}{2}\ m\ v_{i} ^{2} =\frac{1}{2} \ 9m\ [(\frac{7}{9}) ^{2}\ v_{i} ^{2}+ (\frac{2}{9}) ^{2}\ v_{2y} ^{2}]+ m\ v_{2y} ^{2}$

Putting in one side of the equation each speed we get

$\frac{25}{9}\ m\ v_{i} ^{2} =\frac{11}{9}\ m\ v_{2y} ^{2}\\v_{2y} =-1,51\ v_{i}$

We know that the particle 2m travels in the -y axis because it was stated in the question.

Now we can get the y component of the speed of the 9m particle:

$v_{1y} =\frac{2}{9}\ v_{2y} \\v_{1y} =-0,335\ v_{i}$

the magnitude of the final speed of the particle 9m is

$v_{1f} =\sqrt{v_{1x} ^{2}+v_{1y} ^{2} }$

$v_{1f} =\sqrt{(\frac{7}{9}) ^{2}\ v_{i} ^{2}+(-0,335)^{2}\ v_{i} ^{2} }\Rightarrow \ v_{1f} =0,85\ v_{i}$

The tangent that the speed of the particle 9m makes with the -y axis is

$tan(\theta)=\frac{v_{1x} }{v_{1y}} =-2,321 \Rightarrow\theta=-66,68^{o}$

As a vector the speed of the particle 9m is:

$\vec{v_{1f} }=\frac{7}{9} v_{i} \hat{x}-0,335\ v_{i}\ \hat{y}$

As a vector the speed of the particle 2m is:

$\vec{v_{2f} }=-1,51\ v_{i}\ \hat{y}$

8 0

3 years ago

A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t

Novosadov [1.4K]

Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C

8 0

3 years ago

Read 2 more answers

Bob is watching Anna fly by in her new high-speed plane, which Anna knows to be 60 m in length. As a greeting, Anna turns on two

vlada-n [284]

Answer:

0.196*c

Explanation:

A good thing to remember is that once you have the position and the time in one frame we can figure out corresponding position and time in another frame in other frames given their relative velocities.

Anna moves in (S') frame and we are given two events synchronized in her frame with the distance between them, Hence using Lorentz transformation to show which event Bob frame (S) will see first:

Hence,

$dt = y (dt' + \frac{v*dx}{c^2} ) \\\\dt' = 0\\dx' = 60 m\\\\t_2 - t_1 = \sqrt{\frac{1}{(1 - v^2/c^2) } } * (\frac{v*(x_2 - x_1)}{c^2} )$

we are assuming that dx' > 0 , hence we are saying that light emitted from front end of the plane is event number two and that coming from the back end is event number one. As the time in Bob's frame turns out to be positive, this means that event number two happened after event number one in his frame, in other words, the light emitted from the back end of Anna's plane arrives first to Bob's eyes.

Given:

dt' = 40ns

dt = 0

dx' = 60

Solution:

$dt' = \sqrt{\frac{1}{(1 - v^2/c^2) } } * (\frac{v*dx'}{c^2} )\\\\\sqrt{1 - \frac {v^2}{c^2 } } = (\frac{v*dx'}{c^2*dt} )\\\\v^2 = \frac{c^4*dt^2}{c^2*dt^2 + dx'^2}\\\\v = \frac{c^2*dt}{\sqrt{c^2*dt^2 + dx'^2} }\\\\v = \frac{(3*10^8)^2*40*10^9}{\sqrt{(3*10^8)^2*(40*10^9)^2 + 60^2} }\\\\v = \frac{3.6*10^9}{61} \\\\v = 0.196 c$

8 0

3 years ago

A train traveling at 50 miles per hour has to slow down to 10 miles per hour in 4 seconds. What is the acceleration

elena-s [515]

Answer:-10 miles per second

Explanation:

3 0

3 years ago

Read 2 more answers

If a 5-solar-mass black hole has a radius to its event horizon of 15 km, the radius of the event horizon of a 50-solar-mass blac

Arisa [49]

Answer:150km

Explanation:

A 5-solar-mass black hole has radius to its event horizon to be 15 km, then the radius of the event horizon of a 50-solar-mass black hole will be

5solarmass =15km

50solar mass = x

Cross mutiply

x = 50* 15 / 5

15 x 10 = 150km

3 0

3 years ago